我希望我的HQL返回Object而不是数组,因为我使用了一些连接表,当我编写包含连接表的列名的查询时,HQL给出数组列表而不是对象。我发现我们应该使用new
来使它成为对象。HQL不返回对象
SELECT new Accommodation(a.name, a.rank, ap.pic) FROM Accommodation AS a INNER JOIN a.accommodationPics AS ap WHERE ap.isPromoPic = 1 AND a.cbState.stateName = :stateName
我已经尝试过目前为止,并得到错误:'Accommodation' cannot be resolved to a type.
。有什么不对?
更新
新建查询:SELECT new ba.reservation.pojo.Accommodation(a.name, a.rank, ap) FROM Accommodation AS a INNER JOIN a.accommodationPics AS ap WHERE ap.isPromoPic = 1 AND a.cbState.stateName = :stateName
@Column(name = "name", nullable = false, length = 200)
private String name;
@Column(name = "rank")
private int rank;
@OneToMany(mappedBy = "accommodationBean", fetch = FetchType.EAGER, cascade = CascadeType.REMOVE)
@JsonManagedReference
private List<AccommodationPic> accommodationPics;
public Accommodation(String _name, int _rank, ArrayList<AccommodationPic> _pic) {
this.rank = _rank;
this.name = _name;
this.accommodationPics = _pic;
}
1. simas_ch说:加入你的类寄宿完整路径。 2.您是否定义了有关住宿的正确构造方法? –
@JoeTaras我只有一个默认的住宿构造函数。 –
您必须添加一个构造函数(Type1,Type2,Type3)和3种类型的查询 –