删除多维数组中的重复数据（关联数组）

Question

我有三个键指向类型数组的值，在这些数组值中我有重复的值。我怎样才能删除它们？

array(3) { 
["rock"]=> 
array(4) { 
[0]=> 
array(9) { 
    ["id"]=> 
    string(1) "1" 
    ["title"]=> 
    string(15) "Teleman Tickets" 
    ["location"]=> 
    string(20) "Concorde 2, Brighton" 
    ["event_date"]=> 
    string(10) "2017-02-20" 
    ["event_time"]=> 
    string(8) "20:00:00" 
    ["url"]=> 
    string(1) "0" 
    ["geo_lat"]=> 
    string(18) "50.817321799999990" 
    ["geo_long"]=> 
    string(17) "-0.12304610000001" 
    ["tags"]=> 
    string(30) "rock,alternative,indie" 
} 
[1]=> 
array(9) { 
    ["id"]=> 
    string(1) "4" 
    ["title"]=> 
    string(9) "Blink-182" 
    ["location"]=> 
    string(25) "Motorpoint Arena, Cardiff" 
    ["event_date"]=> 
    string(10) "2017-07-03" 
    ["event_time"]=> 
    string(8) "18:00:00" 
    ["url"]=> 
    string(1) "0" 
    ["geo_lat"]=> 
    string(18) "51.478937400000010" 
    ["geo_long"]=> 
    string(17) "-3.17172289999996" 
    ["tags"]=> 
    string(14) "rock,metal" 
} 
[2]=> 
array(9) { 
    ["id"]=> 
    string(1) "8" 
    ["title"]=> 
    string(5) "Ghost" 
    ["location"]=> 
    string(29) "O2 Forum Kentish Town, London" 
    ["event_date"]=> 
    string(10) "2017-03-26" 
    ["event_time"]=> 
    string(8) "19:00:00" 
    ["url"]=> 
    string(1) "0" 
    ["geo_lat"]=> 
    string(18) "51.552197000000010" 
    ["geo_long"]=> 
    string(17) "-0.14196900000002" 
    ["tags"]=> 
    string(30) "rock,alternative,indie" 
} 
[3]=> 
array(9) { 
    ["id"]=> 
    string(2) "10" 
    ["title"]=> 
    string(11) "Courteeners" 
    ["location"]=> 
    string(39) "Emirates Old Trafford, Lancashire C.C.C" 
    ["event_date"]=> 
    string(10) "2017-05-27" 
    ["event_time"]=> 
    string(8) "16:00:00" 
    ["url"]=> 
    string(1) "0" 
    ["geo_lat"]=> 
    string(18) "53.456428000000000" 
    ["geo_long"]=> 
    string(17) "-2.28679699999998" 
    ["tags"]=> 
    string(30) "rock,alternative,indie" 
} 
} 
["alternative"]=> 
array(4) { 
[0]=> 
array(9) { 
    ["id"]=> 
    string(1) "1" 
    ["title"]=> 
    string(15) "Teleman Tickets" 
    ["location"]=> 
    string(20) "Concorde 2, Brighton" 
    ["event_date"]=> 
    string(10) "2017-02-20" 
    ["event_time"]=> 
    string(8) "20:00:00" 
    ["url"]=> 
    string(1) "0" 
    ["geo_lat"]=> 
    string(18) "50.817321799999990" 
    ["geo_long"]=> 
    string(17) "-0.12304610000001" 
    ["tags"]=> 
    string(30) "rock,alternative,indie" 
} 
[1]=> 
array(9) { 
    ["id"]=> 
    string(1) "6" 
    ["title"]=> 
    string(6) "Sum 41" 
    ["location"]=> 
    string(23) "O2 Academy Leeds, Leeds" 
    ["event_date"]=> 
    string(10) "2017-02-26" 
    ["event_time"]=> 
    string(8) "19:00:00" 
    ["url"]=> 
    string(1) "0" 
    ["geo_lat"]=> 
    string(18) "53.802188400000000" 
    ["geo_long"]=> 
    string(17) "-1.54713770000001" 
    ["tags"]=> 
    string(21) "alternative,indie" 
} 
[2]=> 
array(9) { 
    ["id"]=> 
    string(1) "8" 
    ["title"]=> 
    string(5) "Ghost" 
    ["location"]=> 
    string(29) "O2 Forum Kentish Town, London" 
    ["event_date"]=> 
    string(10) "2017-03-26" 
    ["event_time"]=> 
    string(8) "19:00:00" 
    ["url"]=> 
    string(1) "0" 
    ["geo_lat"]=> 
    string(18) "51.552197000000010" 
    ["geo_long"]=> 
    string(17) "-0.14196900000002" 
    ["tags"]=> 
    string(30) "rock,alternative,indie" 
} 
[3]=> 
array(9) { 
    ["id"]=> 
    string(2) "10" 
    ["title"]=> 
    string(11) "Courteeners" 
    ["location"]=> 
    string(39) "Emirates Old Trafford, Lancashire C.C.C" 
    ["event_date"]=> 
    string(10) "2017-05-27" 
    ["event_time"]=> 
    string(8) "16:00:00" 
    ["url"]=> 
    string(1) "0" 
    ["geo_lat"]=> 
    string(18) "53.456428000000000" 
    ["geo_long"]=> 
    string(17) "-2.28679699999998" 
    ["tags"]=> 
    string(30) "rock,alternative,indie" 
} 
} 
["sax"]=> 
array(1) { 
[0]=> 
array(9) { 
    ["id"]=> 
    string(1) "3" 
    ["title"]=> 
    string(9) "Take That" 
    ["location"]=> 
    string(22) "The SSE Hydro, Glasgow" 
    ["event_date"]=> 
    string(10) "2017-05-11" 
    ["event_time"]=> 
    string(8) "18:30:00" 
    ["url"]=> 
    string(1) "0" 
    ["geo_lat"]=> 
    string(18) "55.860156000000000" 
    ["geo_long"]=> 
    string(17) "-4.28525800000000" 
    ["tags"]=> 
    string(24) "pop,boy-band,sax" 
} 
} 
} 

Answer 1

我会假设，如果两个频段具有相同的“身份证”，那么它们是相同的

$unique_bands = array(); 
// if the master array is called bands  
foreach($bands as $genre){ 
    foreach($genre as $band){ 
     $unqiue_bands[$band['id']] = $band; 
    } 
} 

也许把$unique_bands = array_values(array_filter($unique_bands));末重新索引阵列

Answer 2

您对official documentation的解决方案......一个人做了一个简单的功能做你想要什么。

实例阵列：

<?php 
$details = array( 
    0 => array("id"=>"1", "name"=>"Mike", "num"=>""), 
    1 => array("id"=>"2", "name"=>"Carissa", "num"=>"08548596258"), 
    2 => array("id"=>"1", "name"=>"Mathew", "num"=>"784581254"), 
); 
?> 

功能：

<?php 
function unique_multidim_array($array, $key) { 
    $temp_array = array(); 
    $i = 0; 
    $key_array = array(); 

    foreach($array as $val) { 
     if (!in_array($val[$key], $key_array)) { 
      $key_array[$i] = $val[$key]; 
      $temp_array[$i] = $val; 
     } 
     $i++; 
    } 
    return $temp_array; 
} 
?> 

你必须修复它的工作您的阵列尺寸。