2012-07-24 41 views
0

在下面的代码,复选框没来任何一个可以帮助我的Table.Can的第一排..复选框内部,而在PHP

RGDS, Sirojan

<body> 
<form method="post" action="<?php echo $_SERVER['PHP_SELF'];?>" 

<?php 
$dbc=mysqli_connect("localhost","root","","elvis_store") or die("Error Connecting to Mysql Database"); 

$query="SELECT * FROM email_list"; 
$result=mysqli_query($dbc,$query)or die("Query Syntaxt is Incorrect"); 

while($row=mysqli_fetch_array($result)){ 

    echo '<input type="checkbox" value="'.$row['id'].'" name="todelete[]"/>'; 
    echo $row['first_name']." ".$row['last_name']." ".$row['email']; 
    echo "<br/>"; 
} 
mysqli_close($dbc); 
?> 

<input type="submit" name"submit" value="Remove"/> 
</body> 
+0

我认为你的代码是不完整的,请发布正确的代码并相应地格式化它 – Satya 2012-07-24 04:14:58

+0

哪里是'

' – diEcho2012-07-24 04:21:54

回答

6

form标签是不是在第一行关闭

<form method="post" action="<?php echo $_SERVER['PHP_SELF'];?>" 

应该

<form method="post" action="<?php echo $_SERVER['PHP_SELF'];?>"> 
+0

谢谢,现在工作正常 – 2012-07-24 04:26:05