我想了解如何在C中以最清洁/最安全的方式解决这个微不足道的问题。这是我的例子:如何正确分配一个新的字符串值?
#include <stdio.h>
int main(int argc, char *argv[])
{
typedef struct
{
char name[20];
char surname[20];
int unsigned age;
} person;
//Here i can pass strings as values...how does it works?
person p = {"John", "Doe",30};
printf("Name: %s; Age: %d\n",p.name,p.age);
// This works as expected...
p.age = 25;
//...but the same approach doesn't work with a string
p.name = "Jane";
printf("Name: %s; Age: %d\n",p.name,p.age);
return 1;
}
编译器的错误是:
main.c: In function ‘main’: main.c:18: error: incompatible types when assigning to type ‘char[20]’ from type ‘char *’
据我所知,C(不是C++)没有字符串类型,而是使用字符数组,所以另一种方式来做到这一点是改变的例子结构保持字符的指针:
#include <stdio.h>
int main(int argc, char *argv[])
{
typedef struct
{
char *name;
char *surname;
int unsigned age;
} person;
person p = {"John", "Doe",30};
printf("Name: %s; Age: %d\n",p.name,p.age);
p.age = 25;
p.name = "Jane";
printf("Name: %s; Age: %d\n",p.name,p.age);
return 1;
}
可正常工作,但我不知道是否有这样做更好的方法。谢谢。
如果我们在'main()'中声明结构体,那么只有人可以在里面访问它。 尝试从主要移出使用它作为全球 – EsmaeelE 2018-03-03 19:58:27