如何触发这两个？

Question

PHP新特性。如果这个问题很荒谬，请原谅我。无论如何，我有一些PHP将数据发送到数据库。下面是它的一些：

else { 

$sql = "INSERT INTO users (username, firstname, lastname, password) 
VALUES ('$username', '$firstname', '$lastname', '$pass')"; 

$sql = "CREATE TABLE $username (
day VARCHAR(10) NOT NULL, 
P1 VARCHAR(10) NOT NULL, 
P1_WORK VARCHAR(30) NOT NULL, 
P2 VARCHAR(10) NOT NULL, 
P2_WORK VARCHAR(30) NOT NULL, 
P3 VARCHAR(10) NOT NULL, 
P3_WORK VARCHAR(30) NOT NULL, 
P4 VARCHAR(10) NOT NULL, 
P4_WORK VARCHAR(30) NOT NULL, 
P5 VARCHAR(10) NOT NULL, 
P5_WORK VARCHAR(30) NOT NULL, 
P6 VARCHAR(10) NOT NULL, 
P6_WORK VARCHAR(30) NOT NULL 
)"; 

if (mysqli_query($con, $sql)) { 
    echo "okay"; 
} else { 
    echo "error"; 
} 
    } 

当我运行此，我仅实现第二$sql=将开展，因为我在同一个实例定义$sql两次。我怎样才能做到这一点，所以这些事件都是一举触发的？谢谢！

编辑：全码

<?php 
echo error_reporting(E_ALL); 
$username = strval($_GET['enteredUserName']); 
$pass = strval($_GET['enteredPassword']); 
$firstname = strval($_GET['enteredFirstName']); 
$lastname = strval($_GET['enteredLastName']); 

$con = mysqli_connect('localhost','XXXX','XXXX','XXXX'); 
if (!$con) { 
    die('Could not connect: ' . mysqli_error($con)); 
} else { 
$sql="SELECT * FROM users WHERE username = '".$username."'"; 
$result = mysqli_query($con,$sql); 
if ($result->num_rows > 0) { 
    echo "pop"; 
} else { 

$sql = "INSERT INTO users (username, firstname, lastname, password) 
VALUES ('$username', '$firstname', '$lastname', '$pass') "; 

$sql = "CREATE TABLE $username (
day VARCHAR(10) NOT NULL, 
P1 VARCHAR(10) NOT NULL, 
P1_WORK VARCHAR(30) NOT NULL, 
P2 VARCHAR(10) NOT NULL, 
P2_WORK VARCHAR(30) NOT NULL, 
P3 VARCHAR(10) NOT NULL, 
P3_WORK VARCHAR(30) NOT NULL, 
P4 VARCHAR(10) NOT NULL, 
P4_WORK VARCHAR(30) NOT NULL, 
P5 VARCHAR(10) NOT NULL, 
P5_WORK VARCHAR(30) NOT NULL, 
P6 VARCHAR(10) NOT NULL, 
P6_WORK VARCHAR(30) NOT NULL 
)"; 

if (mysqli_query($con, $sql)) { 
    echo "okay"; 
} else { 
    echo "error"; 
} 
    } 
mysqli_close($con); 
} 
?> 

Answer 1

使用$sql1和$sql2两个不同的变量为你的两个查询，然后

是（两者在同一时间）： -

if(mysqli_query($con, $sql1) && mysqli_query($con, $sql2)){ 
    echo "Ok"; 
}else{ 
    echo "Error"; 
} 

还是一个接一个： -

if (mysqli_query($con, $sql)) { 
    if(mysqli_query($con, $sql2)){ 
     echo "OK"; 
    }else{ 
     echo "error"; 
    } 
} else { 
    echo "error"; 
} 

或者你需要检查mysqli_multi_query()： -

http://php.net/manual/en/mysqli.multi-query.php

Answer 2

使用不同的变量不同的查询

$sql1 = "INSERT INTO users (username, firstname, lastname, password) 
VALUES ('$username', '$firstname', '$lastname', '$pass')"; 

$sql2 = "CREATE TABLE $username (
day VARCHAR(10) NOT NULL, 
P1 VARCHAR(10) NOT NULL, 
P1_WORK VARCHAR(30) NOT NULL, 
P2 VARCHAR(10) NOT NULL, 
P2_WORK VARCHAR(30) NOT NULL, 
P3 VARCHAR(10) NOT NULL, 
P3_WORK VARCHAR(30) NOT NULL, 
P4 VARCHAR(10) NOT NULL, 
P4_WORK VARCHAR(30) NOT NULL, 
P5 VARCHAR(10) NOT NULL, 
P5_WORK VARCHAR(30) NOT NULL, 
P6 VARCHAR(10) NOT NULL, 
P6_WORK VARCHAR(30) NOT NULL 
)"; 

if (mysqli_query($con, $sql1) && mysqli_query($con, $sql2)) { 
    echo "okay"; 
} else { 
    echo "error"; 
} 

Answer 3

就像u_mulder在评论中说的那样，你可以这样做，就像mysqli_error returns empty string if there is no error occured。

$sql1 = 'first query'; 
$sql2 = 'second query'; 
mysqli_query($h, $sql1); 
mysqli_query($h, $sql2); 
$errorOccured = false; 
if (strlen(mysqli_error($h)) > 1) { 
    $errorOccured = true; 
} 

看看mysqli_error in the manual。或者，正如已经指出的那样，只需执行两个mysqli_queries并检查它们的返回值即可。 或者，如果您需要执行整个查询，也可以使用称为“事务”的事物，查看其中一个注释示例。取自mysqli_rollback in the manual：

$all_query_ok=true; // our control variable 

//we make 4 inserts, the last one generates an error 
//if at least one query returns an error we change our control variable 
$mysqli->query("INSERT INTO myCity (id) VALUES (100)") ? null : $all_query_ok=false; 
$mysqli->query("INSERT INTO myCity (id) VALUES (200)") ? null : $all_query_ok=false; 
$mysqli->query("INSERT INTO myCity (id) VALUES (300)") ? null : $all_query_ok=false; 
$mysqli->query("INSERT INTO myCity (id) VALUES (100)") ? null : $all_query_ok=false; //duplicated PRIMARY KEY VALUE 

//now let's test our control variable 
// This is shorthand if else statement 
// ($statement) ? If true : if false; 
$all_query_ok ? $mysqli->commit() : $mysqli->rollback(); 

$mysqli->close();