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我直接从其他地方复制并粘贴了此代码,这些代码完美地工作我刚刚上传到我自己的服务器上,但没有回应,但肯定有请求进入。我不知道它是如何没有反应,当它是完全相同的代码!有任何想法吗?在Azure上使用PHP的Post方法
<?php
if (isset($_SERVER['HTTP_ORIGIN'])) {
header("Access-Control-Allow-Origin: {$_SERVER['HTTP_ORIGIN']}");
header('Access-Control-Allow-Credentials: true');
header('Access-Control-Max-Age: 86400'); // cache for 1 day
}
// Access-Control headers are received during OPTIONS requests
if ($_SERVER['REQUEST_METHOD'] == 'OPTIONS') {
if (isset($_SERVER['HTTP_ACCESS_CONTROL_REQUEST_METHOD']))
header("Access-Control-Allow-Methods: GET, POST, OPTIONS");
if (isset($_SERVER['HTTP_ACCESS_CONTROL_REQUEST_HEADERS']))
header("Access-Control-Allow-Headers: {$_SERVER['HTTP_ACCESS_CONTROL_REQUEST_HEADERS']}");
exit(0);
}
$postdata = file_get_contents("php://input");
if (isset($postdata)) {
$request = json_decode($postdata);
$username = $request->username;
if ($username != "") {
echo "Server returns: " . $username;
}
else {
echo "Empty username parameter!";
}
}
else {
echo "Not called properly with username parameter!";
}
?>
请贴HTTP请求和响应(如果有的话)的日志 - 感谢 - 和HTTP代码 – danday74