我已经工作了这2天,我不能例如批准,拒绝和待3个不同的状态结合我的表值表的所有值..显示,即使没有在SQL
在此查询它只显示所有已批准的
Select * from
productdesignapproval a,
productinformation b,
department c,
subdivision e,
class f,
subclass g,
productseason h,
year i,
productstylecode j,
productgenericnumber k,
users l
WHERE
a.productinformationID = b.productinformationID AND
b.departmentID = c.departmentID AND
b.subdivisionID = e.subdivisionID AND
b.classID = f.classID AND
b.subclassID = g.subclassID AND
b.productseasonID = h.productseasonID AND
b.yearID = i.yearID AND
a.productinformationID = j.productinformationID AND
a.productinformationID = k.productinformationID AND
l.userID = a.designerID AND a.approvalstatus = 'Approved'
如果我改变了a.approvalstatus待定状态没有将出现
数据库是这样的,如果设计被批准有特定 productstylecodeĴ值,产品genericnumber K,如果不是,这是我的查询
Select * from
productdesignapproval a,
productinformation b,
department c,
subdivision e,
class f,
subclass g,
productseason h,
year i,
users l
WHERE
a.productinformationID = b.productinformationID AND
b.departmentID = c.departmentID AND
b.subdivisionID = e.subdivisionID AND
b.classID = f.classID AND
b.subclassID = g.subclassID AND
b.productseasonID = h.productseasonID AND
b.yearID = i.yearID AND
l.userID = a.designerID AND
a.approvalstatus != 'Approved'
如果该值挂起/拒绝没有productstylecode和genericnumber。
问题如何将2个表格合并为1个表格?所以我可以显示所有批准的产品样式代码和通用编号以及所有待批准和拒绝的产品样式代码和通用编号。谢谢!
您可以用'union'但是请注意,它们必须具有相同的列 – Sherlock
[不良习惯踢:使用旧样式的JOIN(HTTP: //sqlblog.com/blogs/aaron_bertrand/archive/2009/10/08/bad-habits-to-kick-using-old-style-joins.aspx) - 旧式*逗号分隔的表格样式列表*样式在ANSI-** 92 ** SQL标准(**超过20年**之前)中被替换为* proper * ANSI'JOIN'语法,并且不鼓励使用它 –