是否可以从表中返回结果的查询和字段的查询返回

Question

下面是一个查询中使用搜索栏

DECLARE @Temp TABLE (
    [CoreTable] VARCHAR(250), 
    [CoreTableDecription] VARCHAR(250), 
    [FieldName] VARCHAR(250), 
    [cnt] VARCHAR(250) 
       ) 
declare @Keyword1 VARCHAR(100) = '%Prob%' 
declare @Keyword2 VARCHAR(100) = '%Prob%' 
-------------------------------------------------------------- 
INSERT INTO @Temp (CoreTable, CoreTableDecription, FieldName, cnt) 
VALUES 

('PRO','PROTOS_PersonalInformation','AnyCommunicationProblem','1'), 
('PRO','PROTOS_PersonalInformation','SightProblems','1'), 
('PRO','PROTOS_PersonalInformation','SpeechProblems','1'), 
('PRO','PROTOSMODEL_Antenatal_Status','Other_Antenatal_Problems','1'), 
('PRO','PROTOSMODEL_Antenatal_Status','Other_Antenatal_Problems_Text','1'), 
('PRO','PROTOSMODEL_Baby_Details','Neonatal_medical_problems','1'), 
('PRO','PROTOSMODEL_Baby_Details','Neonatal_medical_problems_Text','1'), 
('PRO','PROTOSMODEL_Baby_Postnatal','Any_skin_problems_detected','1'), 
('PRO','PROTOSMODEL_Baby_Postnatal','Any_skin_problems_detected_Bruising','1'), 
('PRO','PROTOSMODEL_Baby_Postnatal','Any_skin_problems_detected_Naevus','1'), 
('PRO','PROTOSMODEL_Baby_Postnatal','Any_skin_problems_detected_Rash','1'), 
('PRO','PROTOSMODEL_Baby_Postnatal','Any_skin_problems_detected_Text','1') 

Select * from @Temp 

这是伟大的发现/搜索和使用的查询是下面的结果

declare @Keyword1 VARCHAR(100) = '%Prob%' 
declare @Keyword2 VARCHAR(100) = '%Prob%' 
select 
    LEFT(o.name,3) CoreTable, 
    o.name CoreTableDesc, 
    --o.name AS TableName, 
    c.name AS FieldName 
    ,COUNT(c.name) cnt 
    from sys.columns c 
     inner join sys.objects o on c.object_id=o.object_id 
    where c.name LIKE @Keyword1 
    and LEFT(o.name,3)  in ('PRO') 
    and c.name LIKE @Keyword2 
    GROUP BY c.name, LEFT(o.name,3), o.name 
-- order by LEFT(o.name,3), c.name 

但是什么话，我需要做的是手动运行查询，以确定该列/表中的值（见下文）：

select AnyCommunicationProblem, count(*) cnt 
from PROTOS_PersonalInformation 
GROUP BY AnyCommunicationProblem 

这将返回simplythe行NULL - 2682，否 - 87687，是的 - 135478

我想知道是否有一种方法可以从显示的表名和列名第一查询的结果自动执行此

Answer 1

感谢所有的答案是低于，但我不确定如何得到，如果数据项的计数

DECLARE 
@TABLENAME VARCHAR(255), 
@FIELDNAME VARCHAR(255), 
@SQL VARCHAR(MAX), 
@FieldNamePart1 as varchar(50), 
@FieldNamePart2 as varchar(50) 

SET @SQL = '' 
SET @FieldNamePart1 = 'Type' 
SET @FieldNamePart2 = 'Method' 

IF @FieldNamepart2 = '' 
     DECLARE CRS CURSOR FOR 
     SELECT TABLE_NAME, COLUMN_NAME 
     FROM INFORMATION_SCHEMA.COLUMNS 
     WHERE CHARINDEX('PROTOSMODEL',TABLE_NAME) <> 0 
       AND CHARINDEX(@FieldNamePart1, COLUMN_NAME) <> 0 
--    AND CHARINDEX('DATE', COLUMN_NAME) = 0 
--    AND CHARINDEX('TIME', COLUMN_NAME) = 0 
ELSE 
     DECLARE CRS CURSOR FOR 
     SELECT TABLE_NAME, COLUMN_NAME 
     FROM INFORMATION_SCHEMA.COLUMNS 
     WHERE CHARINDEX('PROTOSMODEL',TABLE_NAME) <> 0 
       AND CHARINDEX(@FieldNamePart1, COLUMN_NAME) <> 0 
       AND CHARINDEX(@FieldNamePart2, COLUMN_NAME) <> 0 
--    AND CHARINDEX('DATE', COLUMN_NAME) = 0 
--    AND CHARINDEX('TIME', COLUMN_NAME) = 0 

OPEN CRS 

FETCH NEXT FROM CRS INTO @TABLENAME, @FIELDNAME 

WHILE @@FETCH_STATUS = 0 
BEGIN 
--  SET @SQL = @SQL + CAST('SELECT DISTINCT ''' AS VARCHAR(MAX)) + CAST(@TABLENAME AS VARCHAR(MAX)) + CAST(''' AS PROTOSMODEL_TABLE, ''' AS VARCHAR(MAX)) + CAST(@FIELDNAME AS VARCHAR(MAX)) + CAST(''' AS PROTOSMODEL_FIELD, ' AS VARCHAR(MAX)) + CAST(@FIELDNAME AS VARCHAR(MAX)) + CAST(' AS FIELD_VALUE FROM ' AS VARCHAR(MAX)) + CAST(@TABLENAME AS VARCHAR(MAX)) + CAST(' UNION ALL ' AS VARCHAR(MAX)) 
     SET @SQL = @SQL + 'SELECT DISTINCT ''' + @TABLENAME + ''' AS PROTOSMODEL_TABLE, ''' + @FIELDNAME + ''' AS PROTOSMODEL_FIELD, [' + @FIELDNAME + '] AS FIELD_VALUE FROM ' + @TABLENAME + ' UNION ALL ' 
     FETCH NEXT FROM CRS INTO @TABLENAME, @FIELDNAME 
END 
CLOSE CRS 
DEALLOCATE CRS 
SET @SQL = SUBSTRING(@SQL, 1, LEN(@SQL) - 10) 
EXEC (@SQL) 
GO