Oracle过程'out''varchar2'表类型参数

Question

我想获得在一个过程（b）中分配的列表，并将其作为OUT参数返回给过程中的类型为'table of varchar2'的变量（一个）。我如何定义OUT参数类型？

前。）

procedure_a() 
type t_list IS TABLE OF VARCHAR2(10) 

l_list t_list; 

procedure_b(l_list); 

end procedure_a; 

procedure_b(out_list OUT ????) 

会是什么类型OUT呢？

在此先感谢。

Answer 1

该类型需要在A和B都可以引用的地方声明。一种选择是声明类型的包装，即

SQL> create package some_pkg 
    2 as 
    3 type t_list is table of varchar2(10); 
    4 
    5 procedure procedureA; 
    6 procedure procedureB(p_list OUT t_list); 
    7 end; 
    8 
    9/

Package created. 

SQL> create or replace package body some_pkg 
    2 as 
    3 procedure procedureA 
    4 as 
    5  l_list t_list; 
    6 begin 
    7  procedureB(l_list); 
    8  dbms_output.put_line(l_list.count); 
    9 end; 
10 
11 procedure procedureB 
12  (p_list OUT t_list) 
13 as 
14 begin 
15  select ename 
16  bulk collect into p_list 
17  from emp; 
18 end; 
19 end; 
20/

Package body created. 

SQL> exec some_pkg.procedureA; 
16 

PL/SQL procedure successfully completed. 

另一种选择是声明类型的SQL，即

SQL> create type t_list 
    2  as table of varchar2(10); 
    3/

Type created. 

SQL> ed 
Wrote file afiedt.buf 

    1 create or replace procedure procedureB(p_list OUT t_list) 
    2 as 
    3 begin 
    4 select ename 
    5  bulk collect into p_list 
    6  from emp; 
    7* end; 
SQL>/

Procedure created. 

SQL> create or replace procedure procedureA 
    2 as 
    3 l_list t_list; 
    4 begin 
    5 procedureB(l_list); 
    6 dbms_output.put_line(l_list.count); 
    7 end; 
    8/

Procedure created. 

SQL> exec procedureA; 
16 

PL/SQL procedure successfully completed.