转换的NSArray到NSDictionary中的切片

Question

我有这样的NSArray：

{name="LOBSTER",photo="prawn.jpg"},{name="COW", photo"cow_grass.png"},...so on 

我想创建在UITableView的部分，所以我需要一个像这样的词典：

{L=(name="Lobster";photo="prawn.jpg"),C=(name="COW"; photo="cow_grass.png"),...so on} 

能否请您帮助我告诉我该怎么做？谢谢。

这是我怎么加我的数组：

animalsArray = [[NSMutableArray alloc] init]; 
     //Loop through our JsonDict 
     long countArray = [[dataDict valueForKey:@"animal"]count]; 
     for (int i = 0; i < countArray ; i++) 
     { 
     NSString * cName = [[[dataDict valueForKey:@"animal"]objectAtIndex:i]valueForKey: @"name"]; 
     NSString * cPhoto = [[[dataDict valueForKey:@"animal"]objectAtIndex:i]valueForKey: @"photo"]; 

     [animalArray addObject:[[Animals alloc]initWithName:cName andPhoto:cPhoto]]; 

Answer 1

UPDATE

I now see that you want an object of type Animal instead of an NSDictionary . The line of code which was animal[@"name"] needs to be what ever accessor method to get the name. I updated my code to guess that you need animal.name .

你想要一个完整的指数（所有的值 'A' 的字典 - 'Z' 即使大多数键有一个空数组）？

- (NSDictionary *)fullIndexOfAnimalsFromAnimals:(NSArray *)animals 
{ 
    NSMutableDictionary *result = [NSMutableDictionary dictionary]; 

    // Create a key for each letter of the alphabet. 
    for (char ch = 'A'; ch <= 'Z'; ++ch) { 
     NSString *key = [NSString stringWithFormat:@"%c", ch]; 
     result[key] = [NSArray array]; 
    } 

    // Add all the animals keyed by the first character of their name. 
    for (Animal *animal in animals) { 
     NSString *key = [animal.name substringToIndex:1] uppercaseString]; 
     result[key] = [result[key] arrayByAddingObject:animal]; 
    } 

    return [result copy]; // NSMutableDictionary * to NSDictionary * 
} 

你想要一个部分索引（一个字典只有键有值）吗？

- (NSDictionary *)partialIndexOfAnimalsFromAnimals:(NSArray *)animals 
{ 
    NSMutableDictionary *result = [NSMutableDictionary dictionary]; 

    // Add all the animals keyed by the first character of their name. 
    for (Animal *animal in animals) { 
     NSString *key = [animal.name substringToIndex:1] uppercaseString]; 
     NSArray *value = result[key]; 
     if (value == nil) { 
      result[key] = [NSArray arrayWithObject:animal]; // Create new array 
     } else { 
      result[key] = [value arrayByAddingObject:animal]; // Add to existing 
     } 
    } 

    return [result copy]; // NSMutableDictionary * to NSDictionary * 
} 

---

作为第二个更新，有什么奇怪的。

[animalArray addObject:[[Animals alloc] initWithUser_id:cUser_id 
               andName:cName 
               andNik:cNik 
              andJob_title:cJob_title 
               andPhone:cPhone 
              andRoom_no:cRoom_no 
               andPhoto:cPhoto]]; 

是animalArray storying Animal *，但你有错误信息似乎表明，NSMutuableArray *对象存储在animalArray。

Answer 2

拿字典，并设置对象的关键

低于

NSMutableArray *arr; 
NSMutableDictionary *dict=[[NSMutableDictionary alloc]init]; 
[dict setObject:arr forKey:@"L"]; 

Answer 3

希望是你正在寻找的代码。

NSArray *currentArray = ... 

// New dictionary object to hold the grouped results. 
NSMutableDictionary *dictionaryWithSections = [NSMutableDictionary dictionary]; 

for (NSDictionary *dictionary in currentArray) { 
    NSString *section = [[[dictionary objectForKey:@"name"] substringToIndex:1] uppercaseString]; 

    // Check whether section already exits. 
    if ([dictionaryWithSections objectForKey:section]) { 
     [[dictionaryWithSections objectForKey:section] addObject:dictionary]; 
    } else { 
     NSMutableArray *sectionData = [NSMutableArray arrayWithObject:dictionary]; 
     [dictionaryWithSections setObject:sectionData forKey:section]; 
    } 
} 

dictionaryWithSections是您用分组获得的新字典。 [dictionaryWithSections allKeys]将返回所需的所有部分标题。即L，C ..等

Answer 4

试试下面代码..

NSMutableDictionary *finalResultDict=[NSMutableDictionary dictionary]; 

    for(NSDictionary *wildanimals in animalsarray) 
    { 

    NSString *key=[[wildanimals[@"name"] substringToIndex:1] uppercaseString]; 

    if([wildanimals[@"name"] hasPrefix:key]) 
    { 
     [finalResultDict setValue: wildanimals forKey:key] ; 
    } 
    } 

您可以通过设置allKeysArray区间的数目计算如下

NSArray * allKeysArray = [finalResultDict allKeys]; 
NSLog(@"Count : %d", [finalResultDict count]); 

希望它可以帮助你......！