通过ID

Question

这里排序列表是我的清单：

data_set = [['ID=j234hg\n'], ['Date=19 October 1969\n'], ['Title=Court Scene With Cardinal Richelieu\n'], ['ID=s4k5jk\n'], ['Date=8 December 1970\n'], ['Title=Crossing The Atlantic On A Tricycle\n'], ['ID=n4j6l3j\n'], ['Date=7 December 1972\n'], '[Title=Mr. Pither']] 

我想通过ID进行排序：这里 是我的代码：

for index,l in enumerate(data_set): 
    if 'ID=' == l[0][:1]: 
     data_set[index]="ID="+l[0][6:].sort() 
print('Sort by ID') 
print(data_set) 
print() 

代码运行，但不排序

Answer 1

考虑到每行的固定长度为三项（即：ID，日期，标题），您可以先对输入进行重新组合，然后进行排序。

rows = [ data_set[i:i+3] for i in range(0,len(data_set), 3)] 
print sum(sorted(rows, key = lambda r:r[0][0]), []) 

输出：

[['ID=j234hg\n'], ['Date=19 October 1969\n'], ['Title=Court Scene With Cardinal Richelieu\n'], ['ID=n4j6l3j\n'], ['Date=7 December 1972\n'], ['Title=Mr. Pither'], ['ID=s4k5jk\n'], ['Date=8 December 1970\n'], ['Title=Crossing The Atlantic On A Tricycle\n']] 

Answer 2

使用集合或字典来完成这类任务。随着名单，你可以最终打印与字“ID”第一要素，但没有相关的数据作为标题，日期等

Answer 3

假设你data_set看起来是这样的：

>>> data_set = [['ID=j234hg\n', 'Date=19 October 1969\n', 'Title=Court Scene With Cardinal Richelieu\n'], ['ID=s4k5jk\n', 'Date=8 December 1970\n', 'Title=Crossing The Atlantic On A Tricycle\n'], ['ID=n4j6l3j\n', 'Date=7 December 1972\n', 'Title=Mr. Pither']] 

尝试

>>> res = sorted(data_set, key=lambda x: x[0]) 
>>> res 
[['ID=j234hg\n', 'Date=19 October 1969\n', 'Title=Court Scene With Cardinal Richelieu\n'], ['ID=n4j6l3j\n', 'Date=7 December 
1972\n', 'Title=Mr. Pither'], ['ID=s4k5jk\n', 'Date=8 December 1970\n', 'Title=Crossing The Atlantic On A Tricycle\n']]