intValue的模糊使用Swift3

我一直在试图将现有的swift2.3转换为swift3。我得到了在下面的代码中对intValue错误模糊使用。intValue的模糊使用Swift3

jobPackageVersion.intJobPackageId =（JobPackageVersionDictionary [ “intJobPackageId”]！作为AnyObject）.intValue作为NSNumber的

这里是全码

if let url = Bundle.main.url(forResource: "tblJobPackageVersion", withExtension: "csv") { 
    do { 
    let strData = try String(contentsOf: url) 
    let csv = CSwiftV(String: strData) 

    if csv.keyedRows != nil { 
     for dictionary in csv.keyedRows! { // [Dictionary<String, String>] 
     let JobPackageVersionDictionary = dictionary as NSDictionary // Cast to NSDictionary 
     let JobPackageVersionEntity = NSEntityDescription.entity(forEntityName: "JobPackageVersion", in: context) 
     let jobPackageVersion = JobPackageVersion(entity: JobPackageVersionEntity!, insertInto: context) 

     // Set object attributes 
     jobPackageVersion.intJobPackageId = (JobPackageVersionDictionary["intJobPackageId"]! as AnyObject).intValue as NSNumber 
     jobPackageVersion.intJobPackageVersionId = (JobPackageVersionDictionary["intJobPackageVersionId"]! as AnyObject).intValue as NSNumber 
     jobPackageVersion.intStatus = (JobPackageVersionDictionary["intStatus"]! as AnyObject).intValue as NSNumber 
     jobPackageVersion.intVersion = (JobPackageVersionDictionary["intVersion"]! as AnyObject).intValue as NSNumber 

     do { // Save object to database and clean up memory 
      try context.save() 
      context.refresh(jobPackageVersion, mergeChanges: false) 
     } catch let error as NSError { Logger.sharedInstance.logMessage("\(#function) JobPackageVersion Saving Error: \(error.userInfo)") } 
     } // for-loop 

     Logger.sharedInstance.logMessage("\(#function): Loaded \(csv.keyedRows!.count) tblJobPackageVersion records.") 
    } else { Logger.sharedInstance.logMessage("\(#function) CSV Parser Warning: no CSV data was parsed in tblJobPackageVersion.csv!") } 
    } catch { Logger.sharedInstance.logMessage("\(#function) Error reading contents of tblJobPackageVersion.csv.") } 
} else { Logger.sharedInstance.logMessage("\(#function) Error locating URL for resource tblJobPackageVersion.csv") } 
}

任何帮助，将不胜感激。

谢谢。

来源

2016-11-08 rsimsek

您正试图对AnyObject类型的对象调用intValue。由于错误状态，这太模糊了，因为NSNumber和NSString都具有intValue属性。 Xcode不知道要使用哪个intValue，因为NSNumber和NSString属于AnyObject保护伞。由于Xcode很混乱，你需要更具体的关于你的对象是什么类型。尝试是这样的：

jobPackageVersion.intJobPackageId = (JobPackageVersionDictionary["intJobPackageId"]! as NSNumber).intValue

注1：你可能要去跟你打电话intValue对其他对象得到了同样的错误，但你可以相应地解决这些问题。

注意2：要非常小心地使用!解开物体的力量。如果你使用的字典返回零，你的程序将崩溃。相反，我会根据您的使用情况安全地使用if let或guard声明对其进行解包。像这样的东西可能工作好一点：

guard let intJobPackageId = JobPackageVersionDictionary["intJobPackageId"] as? NSNumber, 
     let intJobPackageVersionId = JobPackageVersionDictionary["intJobPackageVersionId"] as? NSNumber, 
     let intStatus = JobPackageVersionDictionary["intStatus"] as? NSNumber, 
     let intVersion = JobPackageVersionDictionary["intVersion"] as? NSNumber 
else { 
    print("one of the dictionary values is nil") 
    return 
} 

jobPackageVersion.intJobPackageId = intJobPackageId.intValue 
jobPackageVersion.intJobPackageVersionId = intJobPackageVersionId.intValue 
jobPackageVersion.intStatus = intStatus.intValue 
jobPackageVersion.intVersion = intVersion.intValue

这可能不是你想要什么，但它应该给你如何安全地解开你的对象，使您的应用程序不会崩溃的想法。你可以玩弄它，并决定什么是最适合你的。

来源

2016-12-24 02:29:35 user3353890

intValue的模糊使用Swift3

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