1
我是一个Python新手。我刚刚创建了一个采用二进制补码的程序并将其转换为十进制值。 (转换的方式描述在http://sandbox.mc.edu/~bennet/cs110/tc/tctod.html。)任何人都可以给我一些关于程序格式和效率的建议吗?
我知道如何格式化您的程序和一些关于如何设计您的程序的“良好习惯”有一定的规则。就像你如何放置标题,评论等一样,以及如何设计它的结构。我无法在互联网上找到指南,所以我决定在这里问。
这是我第一次发布在stackoverflow上,所以如果我犯了错误,请耐心等待。 :)
这是我的代码。
def secBiToDecimal(number):
""" This program takes a 2's complement binary number as input and returns its decimal value
"""
output = ""
" Check the sign of this number and calculate its value in according way."
if number[0]=='0':
output += "+"
temp = 0
for i in range(1,len(number)):
temp += (int(number[i]) * (2**(len(number)-i-1)))
output += str(temp)
print output
elif number[0]=='1':
output += "-"
carryout = 1
" flip the digits"
number = list(number)
for i in range(len(number)):
if number[i] == "1":
number[i]='0'
else:
number[i]='1'
" add 1 to number in binary sense "
for i in range(1,len(number)):
if carryout == 0 and number[len(number)-i]=='0':
break
elif carryout == 1 and number[len(number)-i]=='0':
number[len(number)-i]='1'
break
elif carryout == 0 and number[len(number)-i]=='1':
number[len(number)-i]='1'
break
elif carryout == 1 and number[len(number)-i]=='1':
number[len(number)-i]='0'
number = "".join(number)
temp = 0
for i in range(1,len(number)):
temp += int(number[i]) * (2**(len(number)-1-i))
output += str(temp)
print output
请尝试codereview.stackexchange.com,并参阅PEP 8. – geoffspear 2012-03-07 16:21:50
我喜欢google的python风格指南:http://google-styleguide.googlecode.com/svn/trunk/pyguide.html – Wilduck 2012-03-07 16:23:21
要检查语法和pep8合规性,你会发现[flake](http://pypi.python.org/pypi/flake8)有用。 – jcollado 2012-03-07 16:30:36