2016-10-04 76 views
1

我已经阅读了大约10篇关于onclick事件和Widgets的文章,并且我明白它们的实现方式有所不同。然而,尽管其他人的成功,我似乎发现它不可能得到它的工作。我正在使用Android Studio 2.2并创建了一个简单的测试应用程序。我有一个叫做按钮的按钮。当我按下按钮时,我想要吐司显示。Android Widget的Onclick事件

我已经复制了其他帖子中建议的代码。有人可以看一看,看看我是否做错了什么?

public class NewAppWidget extends AppWidgetProvider { 

    private static final String MyOnClick = "myOnClickTag"; 

    protected PendingIntent getPendingSelfIntent(Context context, String action) { 
     Intent intent = new Intent(context, getClass()); 
     intent.setAction(action); 
     return PendingIntent.getBroadcast(context, 0, intent, 0); 
    } 

    void updateAppWidget(Context context, AppWidgetManager appWidgetManager, 
          int appWidgetId) { 

     CharSequence widgetText = context.getString(R.string.appwidget_text); 
     // Construct the RemoteViews object 
     RemoteViews views = new RemoteViews(context.getPackageName(), R.layout.new_app_widget); 


     views.setOnClickPendingIntent(R.id.button, getPendingSelfIntent(context, MyOnClick)); 

     views.setTextViewText(R.id.appwidget_text, widgetText); 



     // Instruct the widget manager to update the widget 
     appWidgetManager.updateAppWidget(appWidgetId, views); 
    } 

    //RemoteViews.setOnClickPendingIntent(R.id.button, getPendingSelfIntent(context, MyOnClick)); 

    @Override 
    public void onUpdate(Context context, AppWidgetManager appWidgetManager, int[] appWidgetIds) { 
     // There may be multiple widgets active, so update all of them 
     for (int appWidgetId : appWidgetIds) { 

      updateAppWidget(context, appWidgetManager, appWidgetId); 
     } 
    } 

    @Override 
    public void onEnabled(Context context) { 
     // Enter relevant functionality for when the first widget is created 
    } 

    @Override 
    public void onDisabled(Context context) { 
     // Enter relevant functionality for when the last widget is disabled 
    } 
    @Override 
    public void onReceive(Context context, Intent intent) { 
     super.onReceive(context, intent);//add this line 
     if (MyOnClick.equals(intent.getAction())){ 
      //your onClick action is here 
      //display in short period of time 
      Toast.makeText(context, "msg msgasdasd", Toast.LENGTH_SHORT).show(); 

     } 
    }; 
} 

回答

2

好的 - 真的很奇怪。重新启动android模拟器,它开始工作。

嗯。

干杯