我对编码相当陌生,并且是全新的图形。我会感激一些方向,因为我一直无法找到我需要的答案。Android - 如何在缩放后找到矩形
我有一个扩展视图的类。我在自定义画布中创建了几个3层结构的矩形。我成功地能够触摸并移动每个矩形。我可以平移整个画布。在我平移之后,我可以移动单个矩形。我可以放大整个屏幕。我不能做的一件事是在缩放之后移动单个矩形。缩放后我无法“找到”反光板。我准备放弃整个自定义视图,并尝试使用imageview或者我可以处理的事情来尝试查看坐标所触及的内容。
我的问题是:你怎么在缩放后找到矩形的坐标?我的猜测是基于画布的移动或画布的比例来重新计算每一个矩形,但显然我错过了一些东西,因为这看起来过于复杂,并且不适合我。
下面是一些代码 - 请原谅这个烂摊子,我只是想让这个想法失败。我尝试过使用矩阵以及计算器中的比例因子,但都没有让我处于正确的位置。 (某些代码不使用 - 我用它,但不能得到它来计算,其中rects是正确的......如果可以的,甚至这样做的正确方法?)
protected void onDraw(Canvas canvas) {
super.onDraw(canvas);
canvas.translate(xOffset, yOffset);
canvas.scale(scaleFactor, scaleFactor);
for (RectF r: RectFs){
paint.setStyle(Paint.Style.STROKE);
paint.setColor(Color.BLACK);
canvas.drawRoundRect(r, 20, 20,paint); //Set a border
paintShader.setStyle(Style.FILL);
paintShader.setShader(new LinearGradient(r.left, r.bottom, r.right, r.top, Color.CYAN, Color.YELLOW, Shader.TileMode.REPEAT));
canvas.drawRoundRect(r, 20, 20, paintShader);
paint.setColor(Color.BLACK);
paint.setTextSize(textSize);
paint.setTypeface(Typeface.defaultFromStyle(Typeface.BOLD));
paint.setLinearText(true);
canvas.drawText(text, r.left+px, r.top+py, paint);
}
}
public boolean onTouchEvent(MotionEvent event) {
scaleGestureDetector.onTouchEvent(event);
touched = true;
if (!panned){
left = event.getX() - rectHeight/2;
top = event.getY() - rectWidth/2;
}
switch (event.getAction()) {
case MotionEvent.ACTION_DOWN:
startPos.set(event.getX(), event.getY());
findWhatWasTouched();
invalidate();
break;
case MotionEvent.ACTION_POINTER_DOWN:
case MotionEvent.ACTION_MOVE:
if (freezeAction)
break;
// Only move if the ScaleGestureDetector isn't processing a gesture.
if (!scaleGestureDetector.isInProgress() && panned) {
xOffset += event.getX() - startPos.x;
yOffset += event.getY() - startPos.y;
} else
resetAllRectsAfterScrollOrZoom();
findWhatWasTouched();
invalidate();
startPos.set(event.getX(), event.getY());
break;
case MotionEvent.ACTION_POINTER_UP:
freezeAction = true;// When two fingers off of zoom, don't let the other finger jump everything around
break;
case MotionEvent.ACTION_UP:
if (!freezeAction){
findWhatWasTouched();
invalidate();
if (panned || zoomed)
resetAllRectsAfterScrollOrZoom();
}
liveRect = null;
panned = false;
freezeAction = false;
xOffset = 0;
yOffset =0;
break;
}
return true;
}
public void resetAllRectsAfterScrollOrZoom(){
float height, width;
for (RectF r: RectFs){
height = r.height();
width = r.width();
if (zoomed){
r.left += (xOffset * scaleFactor);
r.top += (yOffset * scaleFactor);
}else {
r.left += xOffset;
r.top += yOffset ;
}
r.right = r.left + width;
r.bottom = r.top + height;
}
}
public void findWhatWasTouched(){
boolean rectWasTouched = false;
for (RectF r: RectFs){ // Update positions due to a touch event.
if (r.contains(startPos.x, startPos.y)){
if (liveRect == null)
liveRect = r;
rectWasTouched = true;
}
}
if (!rectWasTouched)
panned = true;
if (!zoomed && !panned && liveRect != null){
float height = liveRect.height();
float width = liveRect.width();
liveRect.left = left;
liveRect.top = top;
liveRect.right = liveRect.left + width;
liveRect.bottom = liveRect.top + height; // We have a moving single rect - reset it's position here
}
}
private class ScaleListener extends ScaleGestureDetector.SimpleOnScaleGestureListener {
@Override
public boolean onScale(ScaleGestureDetector detector) {
scaleFactor *= detector.getScaleFactor();
zoomed = true;
// don't let the object get too small or too large.
scaleFactor = Math.max(0.1f, Math.min(scaleFactor, 5.0f));
return true;
}
@Override
public void onScaleEnd(ScaleGestureDetector detector){
zoomed = false;
}
} // End ScaleListener class
} // End view class
最大的问题是因为在缩放之后触摸了rects,当我朝那个方向移动时,将revers进一步向下移动&,呈指数形式......这导致我认为resetAllRects块的缩放部分中的数学错误。但对于我的生活,我无法弄清楚。仍然不知道是否每次重置矩形坐标是否是正确的方法?