如何匹配NodeList中的特定项目并获取它NodeValues？

Question

我有一个带有标签国家携带名称，alpha2和拨号代码的xml文件

现在我有一个字符串值（这是一个拨号代码），我想检查它是否存在于diallingcode标记，如果它它应该返回国家和阿尔法的名称2. 我已经做了一些代码，但一直在我有*的if语句出错。 请帮我解决一下这个问题吗？ 这里是xml文件

<countries> 
<country name="AFGHANISTAN" alpha2="AF" diallingcode="93"/> 
<country name="ÅLAND ISLANDS" alpha2="AX"/> 
<country name="ALBANIA" alpha2="AL" diallingcode="355"/> 
<country name="ALDERNEY"/> 
<country name="ALGERIA (El Djazaïr)" alpha2="DZ" diallingcode="213"/> 
<country name="AMERICAN SAMOA" alpha2="AS" diallingcode="1-684"/> 

这里是我的课堂活动

public class NewTester extends Activity { 
/** Called when the activity is first created. */ 

TextView display; 
String getinput; 
String data,result; 
int code; 
InputStream instream; 

@Override 
public void onCreate(Bundle savedInstanceState) { 
    super.onCreate(savedInstanceState); 
    setContentView(R.layout.main); 
    display=(TextView)findViewById(R.id.tvdisplay); 

    String dphoneNumber="9345678"; 

    data=dphoneNumber.substring(0,2); 



    try { 
     DocumentBuilderFactory dbf=DocumentBuilderFactory.newInstance(); 
     DocumentBuilder db=dbf.newDocumentBuilder(); 
     instream = getResources().openRawResource(R.raw.mycountries); 
     Document doc=db.parse(instream,null); 

     doc.getDocumentElement().normalize(); 

     NodeList nodeList=doc.getElementsByTagName("country"); 

     for(int i=0;i<nodeList.getLength();i++){ 
      Element ele=(Element)nodeList.item(i); 
      NodeList Countryname=ele.getElementsByTagName("name"); 
      NodeList CountryAlpha=ele.getElementsByTagName("alpha2"); 
      NodeList Countrydial=ele.getElementsByTagName("diallingcode"); 
      if(Countrydial.item(0).getNodeValue()==data){//I get error when I run the application from here. 
       result=CountryAlpha.item(0).getNodeValue(); 

      } 
      instream.close(); 

     } 

    } catch (ParserConfigurationException e) { 
     // TODO Auto-generated catch block 
     e.printStackTrace(); 

    } catch (SAXException e) { 
     // TODO Auto-generated catch block 
     e.printStackTrace(); 
    } catch (IOException e) { 
     // TODO Auto-generated catch block 
     e.printStackTrace(); 
    } 
    display.setText(""+result); 
} 
} 

Answer 1

事情是这样的：

 ...... 
     DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); 
     DocumentBuilder db = dbf.newDocumentBuilder(); 
     instream = getResources().openRawResource(R.raw.mycountries); 
     Document doc = db.parse(instream, null); 

     doc.getDocumentElement().normalize(); 

     NodeList nodeList = doc.getElementsByTagName("country"); 

     for (int i = 0; i < nodeList.getLength(); i++) { 
      Node dialingCode = nodeList.item(i).getAttributes().getNamedItem("diallingcode"); 
      if(dialingCode!= null && dialingCode.getNodeValue().equals(dphoneNumber)){ 
       result = nodeList.item(i).getAttributes().getNamedItem("diallingcode").getNodeValue(); 
       break; 
      } 
     } 
     instream.close(); 
     .......