弹簧集成路由器配置

Question

我正在努力寻找使用@Router注释的示例。如果我理解正确的javadoc：

@Service 
public class AgentServiceImpl implements AgentService { 

    @Override 
    @Router(inputChannel = "agentLogin", defaultOutputChannel = "agentServiceResponse") 
    public AgentLoginResponse login(AgentLoginRequest request) { 

    } 
} 

与路由器的XML实例有一个服务的激活，这就是我收到挂在试图弄清楚它是如何将适合在

Answer 1

其实你做错了。见@Router的JavaDoc：

* Indicates that a method is capable of resolving to a channel or channel name 
* based on a message, message header(s), or both. 

所以，你的目标router组件login方法必须返回一个channel name或整个MessageChannel对象。