获取记录计数在单独的列

Question

表：STATUS_TABLE

id | Status | 
================= 
1  true 
2  false 
3  false 
4  true 

我怎样才能获得真正的和单独的列假使用Oracle两者的数量？ 我必须只显示那些状态为真的记录。所以我把条件放在哪里。 但我必须显示两者的数量。 像

MARKED_RECORD UNMARKED_RECORD 
     2    2 

Answer 1

如何像

SELECT SUM(CASE WHEN Status = 'true' THEN 1 ELSE 0 END) MARKED_RECORD, 
     SUM(CASE WHEN Status = 'false' THEN 1 ELSE 0 END) UNMARKED_RECORD 
FROM STATUS_TABLE 

Answer 2

WITH src1 AS 
(
     SELECT 1 id, 'TRUE' status FROM dual UNION ALL 
     SELECT 2 id, 'TRUE' status FROM dual UNION ALL 
     SELECT 3 id, 'FLASE' status FROM dual UNION ALL 
     SELECT 4 id, 'TRUE' status FROM dual UNION ALL 
     SELECT 5 id, 'FLASE' status FROM dual UNION ALL 
     SELECT 6 id, 'TRUE' status FROM dual UNION ALL 
     SELECT 7 id, 'FLASE' status FROM dual 
) 
, src AS 
(
     SELECT id 
     ,  status 
     ,  SUM(DECODE(status, 'TRUE', 1, NULL)) OVER (ORDER BY id) AS is_true 
     ,  SUM(DECODE(status, 'FLASE', 1, NULL)) OVER (ORDER BY id) AS is_false 
     FROM src1 
) 
SELECT s1.id 
,  s1.status 
,  s2.m_is_true 
,  s2.m_is_false 
FROM src s1 
CROSS JOIN 
(
     SELECT MAX(is_true) AS m_is_true 
     ,  MAX(is_false) AS m_is_false 
     FROM src 
) s2 
WHERE s1.status = 'TRUE' 
; 

结果：

ID  STATUS M_IS_TRUE  M_IS_FALSE 
1  TRUE  4    3   
2  TRUE  4    3   
4  TRUE  4    3   
6  TRUE  4    3   

Answer 3

像这样

select decode(status,'true','Marked','false','Unmarked')status, 
     count(status) Count 
from sample_table 
code layoutgroup by status