Python：在另一个类中访问函数

-2

我试图访问另一个类中的函数，并通过“主”类来执行该操作。我已经通过Column 4按钮成功地访问了“master”类，我试图通过列5函数访问主类，然后使其进入窗口类的反应函数，但是当我尝试这样做时，它失败。Python：在另一个类中访问函数

from tkinter import * 

class Window(): 
    def __init__(self, parent, parent_class2): 
     self.parent = parent 
     self.parent_class = parent_class2 
     self.canvas = Canvas(self.parent, width=420, height=360) 
     self.canvas.pack(side="top", fill="both", expand="true") 
     self.cellwidth = 60 
     self.cellheight = 60 
     self.rows = 6 
     self.columns = 7 
     self.rect = {} 
     self.oval = {} 
     self.piece = [] 
     #creates the grid 
     for row in range(6): 
      for column in range(7): 
       x1 = column*self.cellwidth 
       y1 = row * self.cellheight 
       x2 = x1 + self.cellwidth 
       y2 = y1 + self.cellheight 
       self.piece.append(Piece(self.canvas, x1,y1,x2,y2)) 

     self.canvas.itemconfig(self.piece[8].oval, fill="deep pink") 

    def reaction(self): 
     print("In WIndow Class - SUCCESS!") 

class ButtonsExampleGUI: 
    def __init__(self, parent, parent_class): 

     self.parent_class = parent_class 
     self.parent = parent 
     #self.buttons = 7 

     c4 = Button(parent,text = ("Column 4"), command = self.c4_played) 
     c4.pack(side = LEFT) 
     c5 = Button(parent,text = ("Column 5"), command = self.c5_played) 
     c5.pack(side = LEFT) 


    def c4_played(self): 
     self.parent_class.test() 
     print("Col 4") 

    def c5_played(self): 
     print("Col 5") 
     self.parent_class.towindow() 

class Piece: 
    def __init__(self, parent_canvas, x1,y1,x2,y2): 
     self.parent_canvas = parent_canvas 
     self.rect = self.parent_canvas.create_rectangle(x1,y1,x2,y2, fill="grey", tags="rect") 
     self.oval = self.parent_canvas.create_oval(x1+2,y1+2,x2-2,y2-2, fill="white", tags="oval") 

#self class here is being taken as the "parent_class" of the ButtonExampleGUI class 
class Game: 
    def __init__(self, parent): 
     self.parent = parent 
     self.window = Window (self.parent, self) 
     self.buttons = ButtonsExampleGUI (self.parent, self) 

#test being accessed by c4 function calling this within a different class 
    def test(self): 
     print("from parent class") 

    def towindow(self): 
     print("In Game Class") 
     self.parent_class2.reaction() 

if __name__ == "__main__": 
    root = Tk() 
    game = Game(root) 
    root.mainloop()

来源

2015-05-04 PaddyGower

你能提供有关此失败的具体方式更详细？如果有例外，你可以提供这个例外吗？ –

@ eric-scrivner下面是错误'Tkinter回调中的异常 Traceback（最近调用最后一次）： __call__中的第1533行文件“C：\ Python34 \ lib \ tkinter \ __ init__.py”返回self.func * args）文件“H：\ 2015 DTS \ 3.46 \ C4 Revisions \ 4May.py”，第77行，在c5_played中 self.parent_class.towindow（）文件“H：\ 2015 DTS \ 3.46 \ C4 Revisions \ 4May .py“，第109行，在towindow中 self.parent_class2.reaction（） AttributeError：'游戏'对象没有任何属性'parent_class2'' – PaddyGower

应该使用类游戏扩展tkinter吗？ – Scott

也许是因为你没有在游戏中定义parent_class2？请尝试更改高清towindow（个体经营）：

来自：

def towindow(self): 
    print("In Game Class") 
    self.parent_class2.reaction()

到：

def towindow(self):    
    print("In Game Class") 
    self.window.reaction()

来源

2015-05-04 05:13:52 gerumato

Python：在另一个类中访问函数

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