如何创建持久的muc房间中的smack 4.1 beta2

Question

从asmack迁移到smack 4.1 beta2。 创建的muc房间不再持久。

MultiUserChatManager mucm=MultiUserChatManager.getInstanceFor(connection); 
muc=mucm.getMultiUserChat(groupid+"@conference.localhost"); 
DiscussionHistory histroy=new DiscussionHistory(); 
histroy.setMaxStanzas(10); 
muc.createOrJoin(username,null,histroy,SmackConfiguration.getDefaultPacketReplyTimeout()); 
muc.nextMessage(); 

用gajim创建时，房间是持久的。

编辑：这是我们以前使用的代码。默认情况下，聊天室呈持续性，

muc = new MultiUserChat(connection, groupid+"@conference.localhost"); 

if(!muc.isJoined()) 
{ 
DiscussionHistory histroy=new DiscussionHistory(); 
histroy.setMaxStanzas(10); 
muc.join(username,null,histroy,SmackConfiguration.getDefaultPacketReplyTimeout()); 
muc.nextMessage(0); 
} 

Answer 1

您需要设置muc#roomconfig_persistentroom到true在MUC配置从当创建房间。

MultiuserChat muc = manager.getMultiUserChat("myroom@muc.example.org"); 
muc.create("myNick"); 
// room is now created by locked 
Form form = muc.getConfigurationForm(); 
Form answerForm = form.createAnswerForm(); 
answerForm.setAnswer("muc#roomconfig_persistentroom", true); 
muc.sendConfigurationForm(answerForm); 
// sending the configuration form unlocks the room 

请注意，并非所有的XMPP MUC服务都支持持久性会议室。欲了解更多信息，请参阅：

• https://www.igniterealtime.org/builds/smack/dailybuilds/javadoc/org/jivesoftware/smackx/muc/MultiUserChat.html#create(java.lang.String)
• https://www.igniterealtime.org/builds/smack/dailybuilds/documentation/extensions/muc.html
• http://xmpp.org/extensions/xep-0045.html#createroom

Answer 2

您需提交像这样把一个持久组：

private void setConfig(MultiUserChat multiUserChat) { 
    try { 
     Form form = multiUserChat.getConfigurationForm(); 
     Form submitForm = form.createAnswerForm(); 
     for (Iterator<FormField> fields = submitForm.getFields(); fields.hasNext();) { 
      FormField field = (FormField) fields.next(); 
      if (!FormField.TYPE_HIDDEN.equals(field.getType()) && field.getVariable() != null) { 
       submitForm.setDefaultAnswer(field.getVariable()); 
      } 
     } 
     submitForm.setAnswer("muc#roomconfig_publicroom", true); 
     submitForm.setAnswer("muc#roomconfig_persistentroom", true); 
     multiUserChat.sendConfigurationForm(submitForm); 
    } catch (Exception e) { 
     e.printStackTrace(); 
    } 
} 

Answer 3

在咂嘴4.1。 1，@saurabh dixit给出的答案会引发异常。请在点火网站上查看此线程Correct implementation for persistent rooms smack 4.1.1