2015-03-03 44 views
0

我正在为学校建设手风琴,我觉得它应该可以工作。我知道我有一切,直到if else语句。任何建议赞赏手风琴故障我在制作

$(document).ready(function() { 

    // 
    // Set up a click event handler for clicked <li> 
    // 
    $('#accordion li').click(function() { 

     // find first ul that is a child of this (the clicked <li>) 
     var $nextUL = $(this).children('ul:first-child'); 

     // Select all siblings of the clicked <li> and then 
     // select any direct children <ul>'s 
     // that are visible - this is so we can close any visible 
     // <ul> before opening the <ul> for the clicked <li> 
     var $visibleSiblings = $(this).siblings().children('ul:visible'); 

     // If any other <ul>s are visible, slide the visible <ul> 
     // up and then, after the slide up is complete, slide down 
     // the clicked <li>'s <ul> into view 
     if ($visibleSiblings.length > 0) { 
      $visibleSiblings.slideUp('normal', function() { 
      $nextUL.fadeIn('normal'); 
      }); 

     } else { 
      // either no <ul>s were open (open the clicked item) 
      // or the user clicked on the currently open one so close it 
      $nextUL.slideToggle('normal'); 
     } 
    }); 
}); 
+0

您有任何HTML可以使用它,因此我们可以测试吗? – mkaatman 2015-03-03 01:50:20

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在逻辑上似乎没有任何不规则。但对于手风琴,我们预计'fadeIn()'是'slideDown()'。什么是/不是在做什么?在jsfiddle.net中的演示将有所帮助。 – charlietfl 2015-03-03 01:51:15

+0

我从来没有用过jsfiddle,但这里是一个镜头。 http://jsfiddle.net/m6fo2z4y/1/ – cmey5084 2015-03-03 01:55:02

回答