我试图模拟一个存储库并返回保存的同一个对象。当我尝试模拟存储库时出错
这是我的代码片段:
public TransactionType createTransactionType(TransactionTypeEnum type) {
TransactionType transactionType = new TransactionType();
transactionType.setStatus(type.code());
transactionType.setDescription(type.name());
return transactionTypeRepository.save(transactionType);
}
我试图假装是这样的:
1.
public TransactionTypeRepositoryMockBuilder doSave(){
Mockito.when(this.target.save(Mockito.any(TransactionType.class)))
.then(new SaveMock<>())
.then(AdditionalAnswers.returnsFirstArg());
return this;
}
2.
public TransactionTypeRepositoryMockBuilder doSave(){
Mockito.when(this.target.save(Mockito.any(TransactionType.class))).then(new SaveMock<>());
return this;
}
3.
public TransactionTypeRepositoryMockBuilder doSave(){
Mockito.when(this.target.save(Mockito.any(TransactionType.class))).thenReturn(new TransactionType());
return this;
}
4.
public TransactionTypeRepositoryMockBuilder doSave(){
Mockito.when(this.target.save(Mockito.any(TransactionType.class))).then(AdditionalAnswers.returnsFirstArg());
return this;
}
我的生成器类
public class TransactionTypeRepositoryMockBuilder {
private final TransactionTypeRepository target;
private TransactionTypeRepositoryMockBuilder() {
this.target = Mockito.spy(TransactionTypeRepository.class);
}
public static TransactionTypeRepositoryMockBuilder create(){
return new TransactionTypeRepositoryMockBuilder();
}
public TransactionTypeRepository build() {
return this.target;
}
public TransactionTypeRepositoryMockBuilder doSave(){
Mockito.when(this.target.save(Mockito.any(TransactionType.class))).thenReturn(new TransactionType());
return this;
}
}
我收到此错误: _java.lang.NoSuchMethodError:org.mockito.invocation.InvocationOnMock.getArgumentAt(ILjava/lang/Class;)Ljava/lang/Object; _ 我做错了什么?
你是什么mockito版本? – user7294900
这是Mockito 2.8.47 –
我发现你的输入完全令人困惑。你为什么要在称为doSave()的方法中设置你的模拟?因此:请退后一步并向我们展示一个真实的[mcve] - 包括生产和测试用例代码的基本部分。你在这里展示的只是没有多大意义(imho)。 – GhostCat