正确地将输出格式化为文件

Question

我正在解析URL并将它们保存到文件中。我的代码工作正常的Windows，但在Ubuntu它增加了一个小“U”每一行

import re 

reports = "C:\Users/_____/Desktop/Reports/" 
string = "Here is a string to test. http://www.blah.com & http://2nd.com" 
url_match = re.findall(r'(https?://[^\s]+)', string) 
print url_match 

if url_match != []: 
    with open(reports + "_URLs.txt", "a") as text_file: 
     text_file.write('{}'.format(url_match).replace(',', "\n").replace('[', '').replace(']', '').replace("'", '').replace(' ', '').__add__("\n")) 

的前面有没有人对如何解决这种想法？谢谢

Answer 1

'{}'.format(url_match)将url_match列表变成其人类可读的字符串，然后您使用一些复杂的字符串替换回到要写入的行的列表。沿着这条线你会得到一个unicode字符串，因此就是'u'。我不会去猜测为什么发生这种情况，因为真正的解决办法是只处理列表：

import re 

# reports = "C:\Users/_____/Desktop/Reports/" 
reports = "" # for test 
string = "Here is a string to test. http://www.blah.com & http://2nd.com" 
url_match = re.findall(r'(https?://[^\s]+)', string) 
print url_match 
if url_match: 
    with open(reports + "_URLs.txt", "a") as text_file: 
     for url in url_match: 
      text_file.write(url + '\n')