Pinvoke CreateProcess从文件输入/输出

-1

我使用this answer中的示例代码。有用。Pinvoke CreateProcess从文件输入/输出

但我需要将标准输入/输出重定向到文件。进程启动信息结构有字段：

public IntPtr hStdInput; 
public IntPtr hStdOutput; 
public IntPtr hStdError;

我想是这样的：

StartupInfo startupInfo = new StartupInfo(); 
startupInfo.cb = Marshal.SizeOf((object)startupInfo); 
startupInfo.dwFlags = 128; 

FileStream fs = new FileStream(filePath, FileMode.Open); 
startupInfo.hStdInput = fs.Handle;

而且这是行不通的。

如何将文件作为标准输入/输出传递？

UPD1。

我怎么叫CreateProccess：

StartupInfo startupInfo = new StartupInfo(); 
startupInfo.cb = Marshal.SizeOf((object)startupInfo); 
startupInfo.dwFlags = 128; 

FileStream fs = new FileStream(filePath, FileMode.Open); 
startupInfo.hStdInput = fs.Handle; 

Pinvoke.SetErrorMode(ErrorModes.SEM_FAILCRITICALERRORS | ErrorModes.SEM_NOALIGNMENTFAULTEXCEPT | ErrorModes.SEM_NOGPFAULTERRORBOX | ErrorModes.SEM_NOOPENFILEERRORBOX); 
CreationFlags dwCreationFlags = CreationFlags.CREATE_BREAKAWAY_FROM_JOB | CreationFlags.CREATE_SUSPENDED | CreationFlags.CREATE_SEPARATE_WOW_VDM; 
SecurityAttributes securityAttributes = new SecurityAttributes(); 
securityAttributes.bInheritHandle = 1; 
ProcessInformation pi; 

if (!Pinvoke.CreateProcess(null, configuration.RunString, ref securityAttributes, ref securityAttributes, boolInheritHandles: true, dwCreationFlags: dwCreationFlags, lpEnvironment: IntPtr.Zero, lpszCurrentDir: configuration.Directory, startupInfo: ref startupInfo, pi: out pi)) 
    throw new Win32Exception(Marshal.GetLastWin32Error());

UPD2。我加SetHandleInformation通话，但它并不能帮助：根据意见

FileStream fs = new FileStream(@"C:\input.txt", FileMode.Open, FileAccess.Read); 
Pinvoke.SetHandleInformation(fs.Handle, 0x00000001, 0x00000001); 
startupInfo.hStdInput = fs.Handle;

来源

2017-06-18 Backs

文件句柄必须是*可继承*和过程必须用* bInheritHandles == true * – RbMm

@RbMm创建感谢您的评论。我在'CreateProcess'调用和'securityAttributes'中添加了true，但它并没有帮助 – Backs

，但是您需要在创建/打开文件句柄中使用securityAttributes - 而不是进程 – RbMm

。

设置startupInfo.dwFlags到0x00000100

添加新的功能CreateFile：

[DllImport("kernel32.dll", SetLastError = true)] 
public static extern IntPtr CreateFile(string lpFileName, DesiredAccess dwDesiredAccess, uint dwShareMode, ref SecurityAttributes lpSecurityAttributes, CreationDisposition dwCreationDisposition, uint dwFlagsAndAttributes, IntPtr hTemplateFile);

创建输入/输出处理：

var input = Pinvoke.CreateFile(inputFile, DesiredAccess.GENERIC_READ, 0, ref securityAttributes, 
      CreationDisposition.OPEN_EXISTING, 0, IntPtr.Zero); 

var output = Pinvoke.CreateFile(outputFile, DesiredAccess.GENERIC_WRITE, 0, ref securityAttributes, 
      CreationDisposition.CREATE_NEW, 0, IntPtr.Zero); 

startupInfo.hStdInput = input; 
startupInfo.hStdOutput = output; 

... 

public enum DesiredAccess : uint 
{ 
    GENERIC_WRITE = 30, 
    GENERIC_READ = 31 
} 

public enum CreationDisposition : uint 
{ 
    CREATE_NEW = 1, 
    CREATE_ALWAYS = 2, 
    OPEN_EXISTING = 3, 
    OPEN_ALWAYS = 4, 
    TRUNCATE_EXISTING = 5 
}

来源

2017-06-21 14:30:50 Backs

Pinvoke CreateProcess从文件输入/输出

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