大家好我是ajax和JSON的新手,我按照这个指南做了一个jQuery滑块并从数据库中获得一些结果,但它现在正在工作,但现在我只能得到一个结果滑块范围,但我想从该范围内的所有结果,所以我需要从我的PHP传递更多然后一个结果变量,并不能似乎得到它的工作我已经包含下面Ajax JSON传递多个变量
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title></title>
<link rel="stylesheet" href="http://code.jquery.com/ui/1.9.1/themes/base/jquery-ui.css" />
<script src="http://code.jquery.com/jquery-1.8.2.js"></script>
<script src="http://code.jquery.com/ui/1.9.1/jquery-ui.js"></script>
<script src="slider.js"></script>
<link rel="stylesheet" href="style.css" type="text/css">
</head>
<body>
<div>
<span id="deal_min_price"></span>
<span id="deal_max_price" style="float: right"></span>
<br /><br />
<div id="slider_price"></div>
<br />
<span id="number_results"></span> Abonnementer fundet
</div>
</body>
</html>
$(document).ready(function()
{
$("#slider_price").slider({
range: true,
min: 0,
max: 349,
step:1,
values: [ 0, 349 ],
slide: function(event, ui) {
$("#deal_min_price").text(ui.values[0] + "KR");
$("#deal_max_price").text(ui.values[1] + "KR");
},
stop: function(event, ui) {
var dealsTotal = getDeals(ui.values[0], ui.values[1]);
$("#number_results").text(dealsTotal);
},
});
$("#deal_min_price").text($("#slider_price").slider("values", 0) + "KR");
$("#deal_max_price").text($("#slider_price").slider("values", 1) + "KR");
});
function getDeals(min_price, max_price)
{
var numberOfDeals = 0;
$.ajax(
{
type: "POST",
url: 'deals.php',
dataType: 'json',
data: {'minprice': min_price, 'maxprice':max_price},
async: false,
success: function(data)
{
numberOfDeals = data;
}
});
return numberOfDeals;
}
PHP我的代码:
<?php
$result = 0;
define('MYSQL_HOST', 'db564596075.db.1and1.com');
define('MYSQL_USER', 'dbo564596075');
define('MYSQL_PASSWORD', '12345678');
define('MYSQL_DB', 'db564596075');
try
{
$dbh = new PDO('mysql:host='.MYSQL_HOST.';dbname='.MYSQL_DB, MYSQL_USER, MYSQL_PASSWORD);
$dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$dbh->setAttribute(PDO::ATTR_PERSISTENT, true);
$dbh->setAttribute(PDO::ATTR_EMULATE_PREPARES, true);
$dbh->setAttribute(PDO::MYSQL_ATTR_USE_BUFFERED_QUERY, true);
}
catch (PDOException $e)
{
echo 'Fejk: ' . $e->getMessage() . '<br/>';
}
if(isset($_POST['minprice']) && isset($_POST['maxprice']))
{
$minprice = filter_var($_POST['minprice'] , FILTER_VALIDATE_INT);
$maxprice = filter_var($_POST['maxprice'] , FILTER_VALIDATE_INT);
$query = '
SELECT
*
FROM
mobilabonnement
WHERE
Prisprmdr
BETWEEN
:minprice
AND
:maxprice
';
$stmt = $dbh->prepare($query);
try
{
$stmt->bindParam(':minprice', $minprice);
$stmt->bindParam(':maxprice', $maxprice);
$stmt->execute();
}
catch (PDOException $e)
{
print($e->getMessage());
die;
}
$row = $stmt->fetch(PDO::FETCH_ASSOC);
$result = $row['Selskab'];
}
if ($result == true)
{
echo json_encode($result);
}
else{
echo json_encode(0);
}
?>
那么,什么是您的实际问题呢? – 2015-02-07 17:38:00
@ThomasKilian你现在从我的PHP中看到我得到Selskab,但我也想获得id等所有在滑块范围内的行 – Anoxy 2015-02-07 17:39:26