我目前正在尝试根据它们的厚度“3mm”和“5mm”对2个项目列表进行排序。用单选按钮过滤列表
我想为你点击3mm的单选按钮来自动筛选3mm类的物品的清单,而5mm的物品也是如此。然后,如果你点击“无偏好”,我希望它删除任何基于厚度的过滤器。
我一直在搞乱它一段时间,试图拼凑代码,但无济于事,任何帮助将非常感激!谢谢!
的jsfiddle也:http://jsfiddle.net/gdkmrqnr/
HTML:
<div id="container">
<div class="page">
<div>
<h1>piece-y search</h1>
</div>
<div id="main">
<div class="c1">
<h2>piece search</h2>
<div id="piece-search">
<ul class="sort-by">
<li>
<input class="search" placeholder="Search pieces" />
</li>
<li class="sort btn" data-sort="type">Sort by type</li>
<li class="sort btn" data-sort="thickness">Sort by thickness</li>
<li class="sort btn" data-sort="height">Sort by height</li>
<li class="sort btn" data-sort="category">Sort by style</li>
</ul>
<ul class="filter">
<li>
<select name="material" id="filter-material">
<option selected="selected" value="">Select a Material</option>
<option value="plastic">Plastic</option>
<option value="glass">Glass</option>
</select>
</li>
<li>
<input type="radio" name="thickness" value="none" checked>No Preference
</li>
<li>
<input type="radio" name="thickness" value="3mm">3mm
</li>
<li>
<input type="radio" name="thickness" value="5mm">5mm
</li>
<li class="btn" id="filter-none">Show all</li>
<li class="btn" id="filter-scientific" value="category">Only show scientific glass</li>
<li class="btn" id="filter-artsy" value="category">Only show artsy glass</li>
</ul>
<ul class="list">
<li class="item">
<p class="sorting-info hide-this">
<p class="material">plastic</p>
<p class="type">pipe</p>
<p class="thickness">3mm</p>
<p class="height">15inch+</p>
<p class="category">artsy</p>
</p>
</li>
<li class="item">
<p class="sorting-info hide-this">
<p class="material">glass</p>
<p class="type">bowl</p>
<p class="thickness">3mm</p>
<p class="height">14inch-</p>
<p class="category">scientific</p>
</p>
</li>
</ul>
</div>
</div>
</div>
</div> <!-- end of #container -->
JS
// radio button to select thickness
$("input[type='radio']").change(function() {
var number = $("[name='thickness']:checked").val();
var letter = $("[name='thickness']:checked").val();
if (!thickness || !thickness) return;
$("li").hide();
$("li").filter(function (index) {
return $(this).hasClass(thickness) && $(this).hasClass(letter);
}).show();
});
这太棒了,正是我所需要的!非常感谢! 由于我使用了插件list.js,它可能不能在小提琴中工作,但它在本地完美工作! – 2014-11-14 20:37:40