我在活动上下文的<a href tag which has dynamic values. how to open that url in webview?

Question

<string name="xyz">This is my string with url <a href="example://xyz.com:api/deviceconfig/dynamicValue()/something?some_token=dynamic_vlaue&amp; locale=en"></a></string>

dynamic values will change everytime. How to make proper url and open it in webview

Answer 1

Use getString()内的string.xml文件中有一个url到Get String。并在WebView的loadUrl()方法中使用该字符串。

例

String url = getString(R.id.url_in_string); 
yourWebView.loadUrl(url);