阵列的拼接阵列

Question

我有数组的数组：

Array 
(
    [0] => "title" 
    [1] => Array 
     (
      [0] => a 
      [1] => b 
      [2] => c 
     ) 
    [2] => Array 
     (
      [0] => d 
      [1] => e 
      [2] => f 
     ) 
) 

我需要插入一个数组第一个数组像下面

Array 
(
    [0] => "title" 
    [1] => Array 
     (
      [0] => a 
      [1] => b 
      [2] => c 
     ) 
    [2] => Array 
     (
      [0] => a1 
      [1] => b1 
      [2] => c1 
     ) 
    [3] => Array 
     (
      [0] => d 
      [1] => e 
      [2] => f 
     ) 
) 

我不知道如何使用array_splice()。我试过这种方式，但没有奏效。

array_splice($main_array, 2, 0 $array_to_insert) 

Answer 1

$main_array = array(0 => "title",1 => array("a","b")); 

$array_to_insert = array("c","d"); 

$new_array = array_splice($main_array, 1, 0, array($array_to_insert)); 

print_r($main_array); 

Answer 2

nameOfArray [3] = [“d”，“e”，“f”]。此外拼接是好的，但必须像使用：方法Array.splice（指数的howmany，whatToInsert）

Answer 3

我认为这将有助于你...

var a = [1,2,3,4,5]; 
a.splice(2,0,'a','b'); // Returns []; a is [1,2,'a','b',3,4,5] 
a.splice(2,2,[1,2],3); // Returns ['a','b']; a is [1,2,[1,2],3,3,4,5] 

Answer 4

更新：阅读意见后，似乎这是一个JavaScript问题。 :) ?? !!只是为了保持完整性，这是一个PHP的解决方案 - 如要求;）

---

array_splice()是正确的做法。使用下面的代码：

<?php 

$arr = array (
'title', 
array('a', 'b', 'c'), 
array('d', 'e', 'f') 
); 
var_dump($arr); 

// note that I've wrapped the array to be inserted into another, empty, array 
array_splice($arr, 2, 0, array(array('a1', 'b1', 'c1'))); 

// further note that array_splice will not return the new array. $arr is 
// passed by reference and will get modified from inside of array_splice 
var_dump($arr); 

Answer 5

请检查下面的代码

$array_to_insert = array(0 => array(0 => 'a1',1 => 'b1',2 => 'c1')); 
    // You need to have nexted array 

    $main_array = array(0 => "title",1 => array(0 => a,1 => b,2 => c),2 => array(0 => d,1 => 
e,2 => f)); 

    array_splice($main_array, 2, 0, $array_to_insert); 

    var_dump($main_array);