滑动手势滑动UIViews

我想做滑动手势，连续滑动UIView并从中获取数据。考虑每个UIView中的每个单词。我将数据存储在数组中，并在转换时以UIView的标签打印。但是当我显示所有数据程序停止工作后，试图刷卡时。我的项目显示没有错误。请帮助我。滑动手势滑动UIViews

这是我的数组：

addArray = [[NSMutableArray alloc]initWithCapacity:4]; 
[addArray insertObject:@"10" atIndex:0]; 
[addArray insertObject:@"20" atIndex:1]; 
[addArray insertObject:@"30" atIndex:2]; 
[addArray insertObject:@"40" atIndex:3]; 

flippedArray = [[NSMutableArray alloc] initWithCapacity:4]; 
[flippedArray insertObject:@"100" atIndex:0]; 
[flippedArray insertObject:@"200" atIndex:1]; 
[flippedArray insertObject:@"300" atIndex:2]; 
[flippedArray insertObject:@"400" atIndex:3];

这是我的手势识别编码：

-(void)swipegesture:(UISwipeGestureRecognizer *)recognizer{ 

    CGPoint location = [recognizer locationInView:additionalView]; 
    if (recognizer.direction==UISwipeGestureRecognizerDirectionLeft) 
    { 
     if (increment<[addArray count]) 
     { 
      NSLog(@"%d",[addArray count]); 
      increment++; 
      if(increment==[addArray count]) 
      { 
       NSLog(@"Fail"); 
       //[recognizer requireGestureRecognizerToFail:swipeGesture]; 
       [recognizer setEnabled:NO]; 
      } 
      else 
      { 
       additionalLabel.text=[[NSString alloc] initWithFormat:@"%@", 
             [addArray objectAtIndex:increment]]; 
       flippedLabel.text = [[NSString alloc] initWithFormat:@"%@", 
             [flippedArray objectAtIndex:increment]]; 
       NSLog(@"increment %d",increment); 
       [UIView animateWithDuration:0.55 animations:^{ 
        [UIView setAnimationDelay:0.2]; 
       }]; 
       CATransition *animation = [CATransition animation]; 
       [animation setType:kCATransitionPush]; 
       [animation setSubtype:kCATransitionFromRight]; 
       [animation setTimingFunction:[CAMediaTimingFunction 
           functionWithName:kCAMediaTimingFunctionDefault]]; 
       [animation setSpeed:0.4]; 
       [[additionalView layer] addAnimation:animation forKey:nil]; 
      } 
     } 
    } 
    else if(recognizer.direction==UISwipeGestureRecognizerDirectionRight) 
    { 
     if (increment>=0 && increment<[addArray count]) 
     { 
      increment--; 
      if(increment>[addArray count]) 
      { 
       additionalLabel.text=[[NSString alloc]initWithFormat:@"%@", 
             [addArray objectAtIndex:increment]]; 
       flippedLabel.text=[[NSString alloc]initWithFormat:@"%@", 
             [flippedArray objectAtIndex:increment]]; 
       NSLog(@"Decrement %d",increment); 
       [UIView animateWithDuration:0.55 animations:^{ 
        [UIView setAnimationDelay:0.2]; 
       }]; 
       CATransition *animation = [CATransition animation]; 
       [animation setType:kCATransitionPush]; 
       [animation setSubtype:kCATransitionFromLeft]; 
       [animation setTimingFunction:[CAMediaTimingFunction 
           functionWithName:kCAMediaTimingFunctionDefault]]; 
       [animation setSpeed:0.4]; 
       [[additionalView layer] addAnimation:animation forKey:nil]; 
      } 
     } 
    } 
}

这里有一个问题，而仅增加。我将NSLog打印为FAIL。但是，如果它达到[addArray count]的值，我不会如何停止手势识别器。

来源

2012-01-10 Dinesh Raja

我会建议在有效性检查之前递增或递减您的索引值（您命名为increment），并且如果它不是有效的，则在其他操作中反转您的操作。像这样：

if (recognizer.direction==UISwipeGestureRecognizerDirectionLeft) 
{ 
    increment++; 

    if (increment<[addArray count]) 
    { 
     // Your code 
    } 
    else 
    { 
     increment--; // The increment would pass the range of the array, set it back. 
    } 
}

而且对于其他方向也是如此。

编辑：澄清，原来的问题是，你检查，以确保您的索引是有效的，但通过检查后增加最终使其无效。使用你的例子，当增量为3（数组的最高索引）时，它实际上小于数组的数量，即4。然后，将索引增加到4，这会超出范围，或者在的情况下，将陷入如果陈述（这将不再需要使用建议）并记录你的失败。

来源

2012-01-10 18:45:12

正好。如果（增量<[addArray计数]）检查应该是如果（增量+ 1 <[addArray计数]） – Lefteris 2012-01-10 18:53:28

谢谢你这么多的伙计...真的，我很高兴看到你的答案... – 2012-01-11 05:59:37

它的工作完美.. 。 – 2012-01-11 06:00:03

滑动手势滑动UIViews

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