如何对最低值的数组列表对象进行排序？

Question

ArrayList <ShyForeignStockHolding> aithird = new ArrayList<ShyForeignStockHolding>(); 

ShyForeignStockHolding shyfrst = new ShyForeignStockHolding (shyPurchaseSharePrice, shyCurrentSharePrice, shyNumberOfShares, shyCompanyName, shyconversionRate1); 

aithird.add(shyfrst); 

我想Currentshare Price

Answer 1

排序ArrayList您可以使用对象的自定义Comparator，假设你正在使用双为shyCurrentSharePrice：

List<ShyForeignStockHolding> sFSH = new ArrayList<ShyForeignStockHolding>(); 
//add Your objects 
Collections.sort(sFSH, new Comparator<ShyForeignStockHolding>() { 
    @Override public double compare(ShyForeignStockHolding ssh1, ShyForeignStockHolding ssh2) { 
     return ssh1.shyCurrentSharePrice + shh2.shyCurrentSharePrice; //descending use - for Ascending 
    } 

}); 

Answer 2

与Java 8中，您现在可以轻松创建一个Comparator（完全避免匿名类）。由于这是按升序排列，因此您可以在该比较器上调用reversed()使其降序。

Comparator<ShyForeignStockHolding> comparator = Comparator.comparing((sh -> sh.getTheVarYouWantToCompareBy())).reversed(); 
aithird.sort(comparator);