如何让一个contextmenu出现在右键单击datagridview单元格

Question

我有一个带有datagrid的表单。我想要做的是在鼠标右键单击单元格时，鼠标旁边会出现一个下拉菜单。我需要能够从菜单中选择一个选项并运行一些东西。

我可以通过右键点击事件来注册，但是contextmenu不会出现。 下面代码中的菜单应该显示复制单元格的选项。

[void] [System.Reflection.Assembly]::LoadWithPartialName(“System.Windows.Forms”) 
[void] [System.Reflection.Assembly]::LoadWithPartialName(“System.Drawing”) 
$form = New-Object System.Windows.Forms.Form 
$form.Size = New-Object System.Drawing.Size(1040,518) 
$form.KeyPreview = $true 
$form.StartPosition = 'centerscreen' 
$form.BackColor = 'MidnightBlue' 
$form.Add_KeyDown({if($_.KeyCode -eq "Escape"){$form.Close()}}) 
$form.Text = "VIOC Toolkit 5.4" 
$form.Icon = [system.drawing.icon]::ExtractAssociatedIcon($PSHOME + "\powershell_ise.exe") 
$form.MinimumSize = New-Object System.Drawing.Size(1040,525) 

$DataGrid1 = New-Object System.Windows.Forms.DataGridView 
$DataGrid1.Location = New-Object System.Drawing.Size(298,29) 
$DataGrid1.Dock = "Fill" 
$DataGrid1.BorderStyle = 'FixedSingle'  
$DataGrid1.DefaultCellStyle.Font = New-Object System.Drawing.Font($dgfont,$dgfontSize) 
$DataGrid1.AlternatingRowsDefaultCellStyle.BackColor = 'LightGray' 
$DataGrid1.AllowUserToAddRows = $false 
$DataGrid1.RowHeadersVisible = $false 
$DataGrid1.BackgroundColor = "White" 
$DataGrid1.Name="DataGrid1" 
$DataGrid1.Text="DataGrid1" 
$DataGrid1.ColumnCount = 3 
$DataGrid1.Columns[0].Name = 'one' 
$DataGrid1.Columns[1].Name = 'two' 
$DataGrid1.Columns[2].Name = 'three' 
$DataGrid1.Rows.add(@('a', 'b', 'c')) 
$DataGrid1.Rows.add(@('d', 'e', 'f')) 
#*************************************************************#  
$DataGrid1.add_CellMouseClick({ 
    if($_.button -eq 'Right'){ 
     ContextMenu($DataGrid1) 
    } 
}) 

function ContextMenu($Grid){ 
    #create the context menu 
    $menu = New-Object System.Windows.Forms.ContextMenu 
    $CopyMenuItem = New-Object System.Windows.Forms.MenuItem 
    $copymenuItem.text = 'copy' 
    $copymenuItem.add_Click({write-host 'clicked copy'}) 
    $menu.MenuItems.AddRange(@($CopyMenuItem)) 

} 

#***************************************************************# 
$form.Controls.Add($DataGrid1) 
$form.ShowDialog() | out-null 

Answer 1

试试这个代码：

[void] [System.Reflection.Assembly]::LoadWithPartialName(“System.Windows.Forms”) 
[void] [System.Reflection.Assembly]::LoadWithPartialName(“System.Drawing”) 
$form = New-Object System.Windows.Forms.Form 
$form.Size = New-Object System.Drawing.Size(1040,518) 
$form.KeyPreview = $true 
$form.StartPosition = 'centerscreen' 
$form.BackColor = 'MidnightBlue' 
$form.Add_KeyDown({if($_.KeyCode -eq "Escape"){$form.Close()}}) 
$form.Text = "VIOC Toolkit 5.4" 
$form.Icon = [system.drawing.icon]::ExtractAssociatedIcon($PSHOME + "\powershell_ise.exe") 
$form.MinimumSize = New-Object System.Drawing.Size(1040,525) 

[System.Windows.Forms.DataGridView] $DataGrid1 = New-Object System.Windows.Forms.DataGridView 
$DataGrid1.Location = New-Object System.Drawing.Size(298,29) 
$DataGrid1.Dock = "Fill" 
$DataGrid1.BorderStyle = 'FixedSingle'  
#$DataGrid1.DefaultCellStyle.Font = New-Object System.Drawing.Font $dgfont,$dgfontSize 
$DataGrid1.AlternatingRowsDefaultCellStyle.BackColor = 'LightGray' 
$DataGrid1.AllowUserToAddRows = $false 
$DataGrid1.RowHeadersVisible = $false 
$DataGrid1.BackgroundColor = "White" 
$DataGrid1.Name="DataGrid1" 
$DataGrid1.Text="DataGrid1" 
$DataGrid1.ColumnCount = 3 
$DataGrid1.Columns[0].Name = 'one' 
$DataGrid1.Columns[1].Name = 'two' 
$DataGrid1.Columns[2].Name = 'three' 
$DataGrid1.Rows.add(@('a', 'b', 'c')) 
$DataGrid1.Rows.add(@('d', 'e', 'f')) 

#Creation of content click event 
$ClickElementMenu= 
{ 
    [System.Windows.Forms.ToolStripItem]$sender = $args[0] 
    [System.EventArgs]$e= $args[1] 

    $Contentcell=$DataGrid1.Rows[$DataGrid1.CurrentCell.RowIndex].Cells[$DataGrid1.CurrentCell.ColumnIndex].Value 
    $ElementMenuClicked=$sender.Text 
    $RowIndex=$DataGrid1.CurrentCell.RowIndex 
    $ColIndex=$DataGrid1.CurrentCell.ColumnIndex 


    $result="Click on element menu : '{0}' , in rowindex : {1} , column : {2}, content cell : {3}" -f $ElementMenuClicked, $RowIndex, $ColIndex, $Contentcell; 
    Write-Host $result 
} 

#creation menu 
$contextMenuStrip1=New-Object System.Windows.Forms.ContextMenuStrip 

#creation element1 of menu 
[System.Windows.Forms.ToolStripItem]$toolStripItem1 = New-Object System.Windows.Forms.ToolStripMenuItem 
$toolStripItem1.Text = "Element 1"; 
$toolStripItem1.add_Click($ClickElementMenu) 
$contextMenuStrip1.Items.Add($toolStripItem1); 

#creation element2 of menu 
[System.Windows.Forms.ToolStripItem]$toolStripItem2 = New-Object System.Windows.Forms.ToolStripMenuItem 
$toolStripItem2.Text = "Element 2"; 
$toolStripItem2.add_Click($ClickElementMenu) 
$contextMenuStrip1.Items.Add($toolStripItem2); 

#creation event of mouse down on datagrid and show menu when click 
$DataGrid1.add_MouseDown({ 
    $sender = $args[0] 
    [System.Windows.Forms.MouseEventArgs]$e= $args[1] 

    if ($e.Button -eq [System.Windows.Forms.MouseButtons]::Right) 
    { 
     [System.Windows.Forms.DataGridView+HitTestInfo] $hit = $DataGrid1.HitTest($e.X, $e.Y); 
     if ($hit.Type -eq [System.Windows.Forms.DataGridViewHitTestType]::Cell) 
     { 
      $DataGrid1.CurrentCell = $DataGrid1[$hit.ColumnIndex, $hit.RowIndex]; 
      $contextMenuStrip1.Show($DataGrid1, $e.X, $e.Y); 
     } 

    } 
}) 




#***************************************************************# 
$form.Controls.Add($DataGrid1) 
$form.ShowDialog() | out-null 

Answer 2

这里有一个最小的C＃示例

using System; 
using System.ComponentModel; 
using System.Drawing; 
using System.Windows.Forms; 

namespace DataGridViewContextMenu_45574948 
{ 
    public partial class Form1 : Form 
    { 
     BindingList<dgvitem> dgvitems = new BindingList<dgvitem>(); 
     DataGridView dgv = new DataGridView(); 

     public Form1() 
     { 
      InitializeComponent(); 
      InitializeTheGrid(); 
     } 

     private void InitializeTheGrid() 
     { 
      dgv.AutoGenerateColumns = true; 
      dgv.DataSource = dgvitems; 
      dgv.CellMouseClick += Dgv_CellMouseClick; 
      this.Controls.Add(dgv); 
     } 

     private void Dgv_CellMouseClick(object sender, DataGridViewCellMouseEventArgs e) 
     { 
      if (e.Button == MouseButtons.Right) 
      { 
       ContextMenu cm = new ContextMenu(); 
       MenuItem mi = new MenuItem(); 
       mi.Text = "Menu option 1"; 
       mi.Click += MenuItem1Click; 
       cm.MenuItems.Add(mi); 
       mi = new MenuItem(); 
       mi.Text = "Menu option 2"; 
       mi.Click += MenuItem2Click; 
       cm.MenuItems.Add(mi); 
       cm.Show(dgv, new Point(e.Location.X + 10, e.Location.Y + 10)); 
      } 
     } 

     private void MenuItem2Click(object sender, EventArgs e) 
     { 
      //do something here 
     } 

     private void MenuItem1Click(object sender, EventArgs e) 
     { 
      //do something here 
     } 
    } 

    public class dgvitem 
    { 
     public string col1 { get; set; } 
     public string col2 { get; set; } 
     public string col3 { get; set; } 
    } 
}