2016-11-07 150 views
1

我想从html表中提取一个URL。该URL位于td单元格内的锚标签内。 的HTML看起来像:使用Beautiful Soup从td元素中提取URL

<table width="100%" border="0" cellspacing="0" cellpadding="0" name="TabName" id="Tab" class="common-table"> 
    <tr> 
     <td>Acme Company</a><br/><span class="f-10">07-11-2016</span></td> 
     <td><span>Vendor</span><br> 
     <td><a href="http://URL" title="Report Details">Details</a></td> 
    </tr> 
</table> 

这里是Python代码,我已经写了:

from bs4 import BeautifulSoup 
import requests 
import re 

r = requests.get('http://SourceURL') 
soup = BeautifulSoup(r.content,"html.parser") 
# Find table 
table = soup.find("table",{"class": "common-table"}) 
# Find all tr rows 
tr = table.find_all("tr") 

for each_tr in tr: 
    td = each_tr.find_all('td') 
    # In each tr rown find each td cell 
    for each_td in td: 
     print(each_td.text) 
     if(each_td.text == "Details"): 

我走过一路具有URL最后的td标签。我现在如何提取网址?

提前感谢您的时间。

回答

4

像这样:

url = each_td.a['href']

+0

谢谢@Alex大厅 – Ram