我得到了android的线程异常,我打算做的是,当我点击一个按钮,我开始一个线程去动态调用处理程序,处理程序更新整数值的文本视图,而达到整数10,我要停止线程,并有显示一个警告,但它会导致一个错误,我可能做的是如下图所示Android线程异常?
public class sample extends Activity implements Runnable{
public Camcorder()
{
try{
counterThread = new Thread(this);
}catch(Exception ee)
{
}
}
public void run()
{
try{
while(counterFlag)
{
System.out.println("The time starts at : "+counter);
Thread.sleep(1000);
calculate(counter);
counter++;
}
}catch(Exception ee){
System.out.println("Err in ee : "+ee);
}
}
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
c=this.getApplicationContext();
requestWindowFeature(Window.FEATURE_NO_TITLE);
setRequestedOrientation(ActivityInfo.SCREEN_ORIENTATION_LANDSCAPE);
setContentView(R.layout.main);
authalert3 = new AlertDialog.Builder(this);
authalert3.setTitle("Save Video");
authalert3.setMessage("Do you want to save this Video?");
authalert3.setPositiveButton("Yes", null);
Button test = (Button) findViewById(R.id.widget33);
test.setOnClickListener(new View.OnClickListener() {
public void onClick(View v) {
counter = 0;
counterFlag = true;
counterThread.start();
}
});
public void calculate(int counter2) {
// TODO Auto-generated method stub
if(counter2<60){
if(counter2<10)
{
smin="0"+counter2;
}
else{
smin=""+counter2;
}
}
else{
hours++;
counter=0;
smin="00";
if(hours<10){
shours="0"+hours;
}
else{
shours=""+hours;
}
}
handler.sendEmptyMessage(0);
}
Handler handler = new Handler(){
public void handleMessage(android.os.Message msg) {
String tes=shours+":"+smin;
time.setText(tes);
test();
};
};
public void test(){
duration=1;
if(duration==hours){
counterFlag = false;
videoPath=camcorderView.stopRecording();
authalert3.create().show();
counterThread.stop();
}
}
的误差在counterThread.stop抛出();
任何人都建议我,如何解决这个错误。
您需要粘贴错误的异常和调试输出。 – 2011-04-07 09:35:40