遍历列的SQL循环并执行REPLACE语句

Question

我试图在SQL Server中的表中替换CRLF字符。一列的声明的工作原理是这样的：

select REPLACE(REPLACE(col_name,char(13),''), char(10), '') from table_name 

现在我想对我的表中的每一列重复一遍。我有以下脚本，不工作：

Declare @sql varchar(max) = '' 

select @sql = @sql + 'select [' + c.name + '] REPLACE(REPLACE(' + c.name + ', char(13),''), char(10), '') from [' + t.name + ']; ' 
from sys.columns c 
inner join sys.tables t on c.object_id = t.object_id 
where t.name = table_name 

EXEC (@sql) 

不幸的是，这并不工作，我得到了以下错误：

Msg 102, Level 15, State 1, Line 24 
Incorrect syntax near 'REPLACE'. 
Msg 102, Level 15, State 1, Line 24 
Incorrect syntax near 'REPLACE'. 
Msg 102, Level 15, State 1, Line 24 
Incorrect syntax near 'REPLACE'. 
Msg 102, Level 15, State 1 

Answer 1

两件事情; 正如其他答案 所指出的那样，在初始[c.name]之后需要有一个逗号。另外，要在字符串中获得单引号，则需要两个单引号。因此，要将两个单引号放在一起，您需要四个单引号。

select @sql = @sql + 'select [' + c.name + '], REPLACE(REPLACE(' + c.name + ', char(13),''''), char(10), '''') from [' + t.name + ']; ' 
    from sys.columns c 
    inner join sys.tables t on c.object_id = t.object_id 
    where t.name = 'table_name' 

    exec (@sql) 

注：print(@sql)对调试这类问题有很大的帮助！

Answer 2

你可以试试这个方法，变量未设置替换为值，引号不是双引号...

Declare @sql varchar(max) = '' 

select @sql = @sql + 'select [' + c.name + '] = REPLACE(REPLACE(' + c.name + ', char(13),''''), char(10), '''') from [' + t.name + ']; ' 
from sys.columns c 
inner join sys.tables t on c.object_id = t.object_id 
where t.name = 'commasep' 

select @sql 

Answer 3

添加引号，删除第一c.name或添加逗号，而不是添加[]使用QUOTENAME ：

Declare @sql varchar(max) = '' 

select @sql = @sql + 'select ' + QUOTENAME(c.name) + ', REPLACE(REPLACE(' + QUOTENAME(c.[name]) + ', char(13),''''), char(10), '''') from ' + QUOTENAME(t.[name]) + '; ' 
from sys.columns c 
inner join sys.tables t 
    on c.object_id = t.object_id 
where t.[name] = 'table_name' 

EXEC (@sql) 

编辑

如果您需要更新变化@sql部分：

select @sql = @sql + 'UPDATE ' + QUOTENAME(t.[name]) + ' SET ' + QUOTENAME(c.name) + ' = REPLACE(REPLACE(' + QUOTENAME(c.[name]) + ', char(13),''''), char(10), '''') ; '