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我想提出一个简单的PHP REST服务,我打电话,卷曲这里这项服务是该如何使PHP REST服务器发送效应初探回客户端
//client code example
$ch = curl_init($URL);
//curl_setopt($ch, CURLOPT_MUTE, 1);
curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 0);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, 0);
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-Type: text/xml'));
curl_setopt($ch, CURLOPT_POSTFIELDS, $xml);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
$output = curl_exec($ch);
现在对REST服务我收到的代码请求并执行任务。然后我必须将回复发送回去。
//server code example
$xml_post = file_get_contents('php://input');
$xmlparser = new XMLParser;
$parsedata = $xmlparser->parse($xml_post);
$resultobj = new ResultGenerate;
$result = $resultobj->generate($parsedata);
我不知道如何发送reponse($ result)back.So那$输出在最后有xml字符串。请帮忙