如何正确地将此视图保存在模型中

Question

美好的一天我试图将这个视图保存在模型中，但它不起作用。

def my_view(request) 
    data = data['my_data'] 

    if request.method == 'POST': 
     data_a = request.POST.get(data["data_a"]) 
     high_temp = request.POST.get(data["data_b"]) 
     date = request.POST.get(data["data_c"]) 
     wind_speed = request.POST.get(data["data_d"]) 
     obj = WeatherData.objects.create(
      data_a=data_a, data_b=data_b, 
      data_c=data_c, data_d=data_d,) 
     obj.save() 

    return render(request, 'data.html', obj) 

Answer 1

可以使用的ModelForm：https://docs.djangoproject.com/es/1.9/topics/forms/modelforms/#modelform

forms.py: 
class WeatherForm(ModelForm): 
    class Meta: 
     model = Weather 
     fields = ['data_a', 'data_b', 'data_c', 'data_d'] 
views: 
def my_view(request) 
    data = data['my_data'] 
    form = WeatherForm(request.POST or None) 
    if form.is_valid(): 
     obj = form.save() 
    else: 
     obj = None 
    return render(request, 'data.html', {'form': form, 'obj': obj}) 

Answer 2

假设你有POST代码参数应该是这样的：

def my_view(request) 
    data = data['my_data'] 

    if request.method == 'POST': 
     data_a = request.POST.get(data["data_a"]) 
     data_b = request.POST.get(data["data_b"]) 
     data_c = request.POST.get(data["data_c"]) 
     data_d = request.POST.get(data["data_d"]) 
     obj = WeatherData.objects.create(
      data_a=data_a, data_b=data_b, 
      data_c=data_c, data_d=data_d,) 
     # obj.save() --> you don't need save because you already called `create` 

    return render(request, 'data.html', obj)