php aws sdk不能调用lambda函数

Question

使用下面的PHP代码来调用lambda函数，但我得到了下面的错误。看着PHP AWS api文档无法找到造成问题的原因。 接收来自AWS PHP SDK下面的错误

PHP Warning: Illegal string offset 'StatusCode' in /var/www/html/Guzzle/Service/Command/LocationVisitor/Response/StatusCodeVisitor.php on line 21 
PHP Warning: Illegal string offset 'FunctionError' in /var/www/html/Guzzle/Service/Command/LocationVisitor/Response/HeaderVisitor.php on line 24 
PHP Warning: Illegal string offset 'LogResult' in /var/www/html/Guzzle/Service/Command/LocationVisitor/Response/HeaderVisitor.php on line 24 
PHP Catchable fatal error: Argument 1 passed to Guzzle\Service\Resource\Model::__construct() must be of the type array, string given, called in /var/www/html/Guzzle/Service/Command/OperationResponseParser.php on line 86 and defined in /var/www/html/Guzzle/Service/Resource/Model.php on line 20 


use Aws\Lambda\LambdaClient; 
$client = LambdaClient::factory(array(
        'credentials' => array(
        'key' => $f_key, 
        'secret' => $f_secret, 
        ), 
        'region' => 'ap-southeast-2' 
       )); 
    try { 

    echo "new invoke" . "\n"; 
    $result = $client->invoke(array(
     // FunctionName is required 
     'FunctionName' => 'hello_wo’, 
    )); 
    }catch(Exception $e) { 
     echo 'Error retrieving lambd error message code-' . $e->getCode . '-error message-' . $e->getMessage() ; 
    } 

Answer 1

试试这个：

$client = LambdaClient::factory([ 
     'key' => $f_key, 
     'secret' => $f_secret, 
     'region' => 'ap-southeast-2' 
    ]);