删除节点匹配特定属性值的

Question

我有类似XML数据：

<objects> 
    <object> 
    <property name="a" /> 
    <property name="b" /> 
    <property name="hasErrors" /> 
    <property name="data" /> 
     <property/> 
     <property/> 
    </property> 
    </object> 
</objects> 

在PowerShell中，我将如何删除有属性name特定值的节点？更具体地说，我想删除名称为“hasErrors”和“data”的节点及其子节点（如果有的话）。

Answer 1

这个片段应该帮助你，我使用XPath匹配条件：

[xml]$data = @" 
<objects> 
    <object> 
    <property name="a" /> 
    <property name="b" /> 
    <property name="hasErrors" /> 
    <property name="data" /> 
     <property/> 
     <property/> 
    </object> 
</objects> 
"@ 

$data.SelectNodes("//property[@name = 'data' or @name = 'hasErrors']") | % {$_.ParentNode.removechild($_) } | Out-Null 
#to view properties,the empty nodes aren't visible as no value is inside.You can confirm them with count or after saving 
$data.objects.object.property 
$data.Save("C:\yourpath\mydata.xml")