0

好吧,看来我在这个小任务上超出了我的头。我想问一个人如何提交表单,而不依赖URL值?提交表单不依赖于URL

在我的示例中,用户必须先登录才能看到他们的图片库图片。确定这是通过“上下文”,它具有分配给它的活动用户(登录)。道具到@ chem1st & @丹尼尔罗斯曼在早些时候帮助我解释昨天的帮助。现在它可以在登录后在主页中显示自己的用户图库。

我不喜欢用“blahblah.com/bobby/upload”上传,因为它看起来不太安全。我想让登录用户通过“blahblah.com/upload/”上传。这意味着view.py中的表单必须获取以某种方式登录的用户的上下文,并将数据保存到该帐户下的数据库中。

我一直在四处寻找答案,但找不到任何东西。有人能帮助我指出正确的方向吗?

这里是我的models.py

class UserProfile(models.Model): 
    user = models.OneToOneField(User) 
    activation_key = models.CharField(max_length=40, blank=True) 
    key_expires = models.DateTimeField(default=datetime.date.today()) 

    def __str__(self): 
     return self.user.username 

    class Meta: 
     verbose_name_plural='User profiles' 


class ImageDoc(models.Model): 
    user = models.ForeignKey(UserProfile) 
    imgfile = models.ImageField(upload_to='images/') 

forms.py:

class RegistrationForm(UserCreationForm): 
    email = forms.EmailField(required=True, widget=forms.TextInput(attrs={'placeholder': 'E-mail address'})) 
    first_name = forms.CharField(required=True) 
    last_name = forms.CharField(required=True) 


    class Meta: 
     model = User 
     fields = ('first_name', 'last_name', 'email', 'username', 'password1', 'password2') 


    class ImgDocForm(forms.Form): 
     user_file = forms.ImageField() 


    def clean_user_file(self, *args, **kwargs): 
     cleaned_data = super(ImgDocForm,self).clean() 
     user_file = cleaned_data.get("user_file") 

     if user_file: 
      if user_file.size > 5 * 1024 * 1024: 
       raise forms.ValidationError("Filesize is too big.") 

      if not os.path.splitext(user_file.name)[1].strip().lower() in ['.jpg','.png','.gif','.jpeg']: 
       raise forms.ValidationError("File does not look like as picture.") 

     return user_file 


    class UserForm(forms.Form): 
     class Meta: 
      model = User 
      fields = ['first_name', 'last_name', 'password', 'email', 'username'] 

我views.py文件(编辑:更改索引来显示用户的详细信息,画廊,和快速上传功能):

def sign_in(request): 
    context = RequestContext(request) 

    if request.method == 'POST': 
     username = request.POST['username'] 
     password = request.POST['password'] 
     user = authenticate(username=username, password=password) 

     if user: 
      if user.is_active: 
       login(request, user) 
       return HttpResponseRedirect('/', context) 
      else: 
       return HttpResponse("Verify your account!") 
     else: 
      return HttpResponse("Invalid login details supplied.") 


def populateContext(request, context): 
    context['authenticated'] = request.user.is_authenticated() 
    if context['authenticated'] == True: 
     context['username'] = request.user.username 


def index(request): 
    user_details = UserProfile.objects.get(user=request.user) 
    gallery = ImageDoc.objects.filter(user_id=request.user.id) 

    if request.method == 'POST': 
     form = ImgDocForm(request.POST, request.FILES) 
     if form.is_valid(): 
      origin_form = form.cleaned_data["user_file"] 
      origin_name = origin_form.name 

      original_name = ImageDoc(user_id=request.user.id, imgfile=origin_name) 
      original_name.save() 

      return HttpResponse('Saved!') 
    else: 
     form = ImgDocForm() 

    documents = ImageDoc.objects.all() 

    return render(request, 'test.html', {'documents': documents, 'form': form, 'user_details': user_details, 'gallery': gallery}) 




def upload(request): 
    data = {} 
    thumb_size = (100,100) 
    micro_thumb_size = (50,50) 

    if request.method == 'POST': 
     userform = ImgDocForm(request.POST, request.FILES) 

     if userform.is_valid(): 
      origin_form = userform.cleaned_data["user_file"] 
      origin_name = origin_form.name 
      original_file = os.path.join(settings.MEDIA_ROOT, origin_name) 

      . 
      . 
      . 

      original_name = ImageDoc(imgfile=origin_name) 
      original_name.save() 

      . 
      . 
      . 

      userform = ImgDocForm() 
     else: 
      return HttpResponse('Nooo!') 

    else: 
     userform = ImgDocForm() 

    data.update(image_gallery = ImageDoc.objects.only('imgfile')) 
    data.update(userform=userform) 
    data.update(csrf(request)) 
    return render(request, 'upload.html', data) 

编辑:我敢肯定,人们可以清理索引文件显着。另外,底部不是很优雅,但它的工作原理。

而且upload.html文件:

<!DOCTYPE html> 
<html lang="en"> 
<head> 
    <meta charset="utf-8"> 
</head> 
<body> 

<div> 

    <form method="post" action="" enctype="multipart/form-data"> 
     {% csrf_token %} 
     {{ userform.as_p }} 
     <input type="submit"> 
    </form> 

    <br><br> 

    <h2>{{ origin_name }} (original)</h2> 

    {% if origin_name %} 
     <img src="{{ MEDIA_URL }}{{ origin_name }}"> 
    {% endif %} 

    <br><br> 
    {% if image_gallery %} 
     {% for image in image_gallery %} 
      <img src="/{{ image.thumbfile }}"> 
     {% endfor %} 
    {% endif %}  
</div> 
</body> 
</html> 

谢谢!

回答

1

您可以将当前登录的用户视为request.user

+0

感谢您的回复! 所以我应该获得使用该ID,并使用它作为PK,对吗?像这样? userform = ImgDocForm(request.POST,request.FILES,pk = request.user.id) – Bob

+0

@Bob你是否试图从上传的文件中创建ImgDoc?你可以将它分配给你的'ImgDoc.user'字段。如果你想将它分配给表单,请参阅http://stackoverflow.com/questions/18246326/in-django-how-do-i-set-user-field-in-form-to-the-currently-logged-在用户 – serg

+0

感谢您回复@serg!是的,我试图将文件存储到ImgDoc中。你链接的例子似乎并不幸运,但也许我错误地实现了它?目前我正在尝试使用formset来完成这项工作,这是推荐的吗?或者那是错误的方式呢?我之所以用这个原因是因为我之前有一个类似的项目,两个相关的模型,我无法保存到子模型中。使用formsets允许我这样做。 。 但是,在这种情况下,我没有使用从URL中捕获的ID。稍后,我会粘贴下面的当前代码供您检查。 – Bob