我有一个固定的XML模板,并且每个数据的节点可能会增加。 如果我有一个固定的模板。如何在提供父节点名称时迭代所有子节点? 我可以根据xpath制作XML吗?如何使用java制作动态xml
我都有以下代码: -
Map map = hm();
Set set = map.entrySet();
// Get an iterator
Iterator it = set.iterator();
// Display elements
while(it.hasNext()) {
Map.Entry me = (Map.Entry)it.next();
if (check) {
xpath_String+= "|"+me.getKey();
}else {
xpath_String+= me.getKey();
check = true;
}
}
DocumentBuilderFactory domFactory = DocumentBuilderFactory.newInstance();
domFactory.setNamespaceAware(true);
DocumentBuilder builder = domFactory.newDocumentBuilder();
//xml file name acts as template
Document doc = builder.parse("template.xml");
XPathFactory factory = XPathFactory.newInstance();
XPath xpath = factory.newXPath();
XPathExpression expr = xpath.compile(xpath_String);
Object result = expr.evaluate(doc, XPathConstants.NODESET);
NodeList nodes = (NodeList) result;
System.out.println("Total number of tokens: "+nodes.getLength());
//for (int i = 0; i < nodes.getLength(); i++) {
int i=0;
StringTokenizer st = new StringTokenizer(xpath_String,"|");
while (st.hasMoreElements()) {
String val = (String) st.nextElement();
if(hm().containsKey(val)){
System.out.println("Node value is: "+nodes.item(i).getNodeName());
nodes.item(i).setTextContent(hm().get(val).toString());
i++;
}
}
//}
//write the content into xml file
TransformerFactory transformerFactory = TransformerFactory.newInstance();
Transformer transformer = transformerFactory.newTransformer();
DOMSource source = new DOMSource(doc);
// generating the output file name
StreamResult finalResult = new StreamResult(new File("newfxml.xml"));
transformer.transform(source, finalResult);
//making a string for the dom
StringWriter writer = new StringWriter();
StreamResult stResult = new StreamResult(writer);
transformer.transform(source, stResult);
在这里,我有一个固定的模板,我的地图。从地图上我得到了xpath及其相应的值。这只适用于模板xml中没有任何节点重复自身。所以我想知道是否有任何方法可以迭代整个xml节点块,当我得到一个可重复的组件。 有没有这样的解决方案? 或者我需要改变方式我打算继续?
发布您的xml示例。然后告诉我们你有什么尝试。然后告诉我们你卡在哪里了。然后通过例子告诉我们你真正想要的东西。 – darioo 2010-12-14 09:30:55
你有XSD吗?如果是这样,你可以使用类似XMLBeans的东西。 – saugata 2010-12-14 09:35:17
不,我没有XSD .. – sanjay 2010-12-14 09:48:52