我在这里要求您提供一些帮助。我想编写一个读取PGM文件(P2,不是二进制文件)的C代码,并且我已经找到了很多方法在Web上执行它。问题在于,每次我尝试阅读我PC上的一些PGM图像时,我甚至无法正确读取标题,因为它无法识别正确的P2 PGM格式。我总是得到如下错误:“无效的pgm文件类型”或“不支持的格式”。下面是我想要的(最后一个)代码:如何正确读取PGM图像C
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
typedef struct pgm {
int w;
int h;
int max;
int* pData;
} pgm;
int main(int argc, char * argv[]){
char* filename = argv[0];
pgm* pPgm;
FILE* ifp;
int word;
int nRead = 0;
char readChars[256];
//open the file, check if successful
ifp = fopen(filename, "r");
if (!ifp) {
printf("Error: Unable to open file %s.\n\n", filename);
exit(1);
}
pPgm = (pgm *) malloc (sizeof(pgm));
//read headers from file
printf ("Reading PGM file: %s...\n", filename);
fscanf (ifp, "%s", readChars);
if (strcmp(readChars, "P2") == 0) {
//valid file type
//get a word from the file
printf("VALID TYPE.\n");
fscanf (ifp, "%s", readChars);
while (readChars[0] == '#') {
//if a comment, get the rest of the line and a new word
fgets (readChars, 255, ifp);
fscanf (ifp, "%s", readChars);
}
//ok, comments are gone
//get width, height, color depth
sscanf (readChars, "%d", &pPgm->w);
fscanf (ifp, "%d", &pPgm->h);
fscanf (ifp, "%d", &pPgm->max);
printf("WIDTH: %d, HEIGHT: %d\n", pPgm->w, pPgm->h);
// allocate some memory, note that on the HandyBoard you want to
// use constant memory and NOT use calloc/malloc
pPgm->pData = (int*)malloc(sizeof(int) * pPgm->w * pPgm->h);
// now read in the image data itself
for (nRead = 0; nRead < pPgm->w * pPgm->h; nRead++) {
fscanf(ifp, "%d" ,&word);
pPgm->pData[nRead] = word;
// printf("nRead = %d %d\n",nRead,pPgm->pData[nRead]);
}
printf ("Loaded PGM. Size: %dx%d, Greyscale: %d \n",
pPgm->w, pPgm->h, pPgm->max + 1);
}
else {
printf ("Error: %s. Format unsupported.\n\n", readChars);
exit(1);
}
fclose(ifp);
return 0;
}
也许你的PGM不正确。它应该是一个简单的ASCII文件,用选择的代码编辑器打开它,并根据[规范](http://netpbm.sourceforge.net/doc/pgm.html)进行验证。 – usr2564301
请注意,他们说[你不应该在C]中输入'malloc()'的结果(http://stackoverflow.com/questions/605845/do-i-cast-the-result-of-malloc)。 – MikeCAT
我打开了每一张pgm图片,所有图片看起来都是正确的。 – sibly22