以不同的方式

Question

这是我的查询

 $query="SELECT parent.name, parent.depth 
     FROM address AS node, 
       address AS parent 
     WHERE node.name LIKE '%".$name."%' AND 
     node.lft BETWEEN parent.lft AND parent.rgt 
     order by node.lft, parent.rgt"; 

限制的结果，这是我的表结构：

name  |lft | rgt | depth| 
------------+----+-----+------+ 
Australia | 1 | 10 | 1 | 
nsw   | 2 | 9 | 2 | 
sydney  | 3 | 8 | 3 | 
kensington | 4 | 5 | 4 | 
kingsford | 6 | 7 | 4 | 
------------+----+-----+---- -+ 

让我们假设$name = 10k，则其结果将是

name  |depth| 
------------+-----+ 
kingsford | 4 | 
sydney  | 3 | 
nsw   | 2 | 
Australia | 1 | 
kensington | 4 | 
sydney  | 3 | 
nsw   | 2 | 
Australia | 1 | 

我将展示他们是这样的：

-->kensington, sydney, nsw, australia 
-->kingsford, sydney, nsw, australia 

我不能限制这顶多只涉及10个地址。如果我加入limit 2例如，它不会显示上述两个地址。它只会显示这个-->kensington, sydney。我怎样才能做到这一点？

Answer 1

也许问题不是太清楚，但如果我理解正确的话，我会用这样的：

SELECT 
    GROUP_CONCAT(parent.name ORDER BY parent.depth DESC) AS name 
FROM 
    address AS node JOIN address AS parent 
    ON node.lft BETWEEN parent.lft AND parent.rgt 
WHERE node.name LIKE '%k%' 
GROUP BY node.name 
LIMIT 10 

请参阅小提琴here。

编辑

你可能也想利用这一点，返回在原始格式的行：

SELECT 
    parent.name, parent.depth 
FROM 
    (SELECT name, lft FROM address WHERE name LIKE '%k%' LIMIT 10) AS node, 
    address AS parent 
WHERE 
    node.lft BETWEEN parent.lft AND parent.rgt 
order by node.lft, parent.rgt