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我是新来的Java编程,甚至新到Java网络规划,所以我相信这个问题将是一个简单的。我的程序基于提交按钮,将学生ID提交给服务器。我的Java服务器/客户端程序只会工作,每次我第三次运行
前两次我运行它会建立与服务器的连接,然后一切都会崩溃,它永远不会交换串的程序。
但是,每次我第三次运行它,它会很好地工作和交流的字符串作为设计的。
客户:
String currentButton = e.getActionCommand();
if(currentButton == "submit"){
try{
Socket server = new Socket("Localhost",1234);
InetAddress address=InetAddress.getLocalHost();
System.out.println("Connected to "+server.getInetAddress());
System.out.println("Connected to "+address);
BufferedReader br = new BufferedReader(new InputStreamReader(server.getInputStream()));
PrintWriter pw = new PrintWriter(server.getOutputStream(), true);
pw.println(student);
while ((student = br.readLine()) != null) {
System.out.println(student);
pw.println("bye");
if (student.equals("bye"))
break;
}
br.close();
pw.close();
server.close();
} catch (IOException ex){
//ignore exception
}
}
服务器
class NETCW1S {
public static void main(String[] args) throws IOException {
String student;
ServerSocket serverSock = null;
InetAddress address=InetAddress.getLocalHost();
try{
serverSock = new ServerSocket(1234);
System.out.println("Waiting for client connection");
} catch (IOException e) {
System.err.println("Could not listen on port: 1234");
System.exit(1);
}
Socket clientSock = null;
try{
clientSock = serverSock.accept();
} catch (IOException e) {
System.err.println("Accept Failed");
System.exit(1);
}
while (true) {
System.out.println("Connected to "+address);
System.out.println("Waiting for client...");
Socket client = serverSock.accept();
System.out.println("Client from "+client.getInetAddress()+" connected.");
Socket fromClientSocket = serverSock.accept();
PrintWriter pw = new PrintWriter(fromClientSocket.getOutputStream(), true);
BufferedReader br = new BufferedReader(new InputStreamReader(fromClientSocket.getInputStream()));
while ((student = br.readLine()) != null) {
System.out.println("The message: " + student);
if (student.equals("bye")) {
pw.println("bye");
break;
} else {
student = "Server returns " + student;
pw.println(student);
}
}
pw.close();
br.close();
fromClientSocket.close();
}
}
提前非常感谢!
您try子句中执行接近是一个坏主意!如果之前抛出异常,则不会关闭流/连接,这也可能解释您的问题。同样糟糕的,如果不是更糟的是*隐藏例外*!不要这样做,即使你不期待他们! – Neil
“一切都会崩溃”是什么意思? –
喜尼尔,如果我移动试结束的外,该计划不会编译生成错误“NETCW1.java:70:错误:无法找到符号 \t \t br.close();” – George