阅读文件，跳过不需要的行并添加到列表中

Question

我有以下代码，我扫描每行并放入列表中。如果该行匹配 一个字符串“新变化”，我不想列入清单。有关如何实现这一目标的任何建议？

with open('file.txt', 'rb') as f: 
    mainlist = [line.strip() for line in f] 

Answer 1

列表理解也可以做过滤：

mainlist = [line.strip() for line in f if "New changes" not in line] 

Answer 2

with open('file.txt', 'rb') as f: 
    mainlist = [] 
    for line in f: 
     s = line.strip() 
     if s != "New changes": 
      mainlist.append(s) 

如果任何人有一个更Python的方式来做到这一点，随时让我知道。

Answer 3

，可以在列表中理解过滤：

mainlist = [line.strip() for line in f if line.strip() != "New changes"] 

Answer 4

悟也可以接受的条件。尝试：

mainlist = [line.strip() for line in f if line != "New changes"] 

或

mainlist = [line.strip() for line in f if "New changes" not in line] 

Answer 5

只是要在这里不同的是减少的学校和正则表达式的咒语：

import re 
with open('file.txt', 'rb') as f: 
    mainlist = reduce(lambda x, y: x+re.findall("^((?!.*New changes).*)\n?$", y), f.readlines(), [])