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我试图单元测试与RestTemplate发送到API的请求,并从中获取一些资源次年春天启动代码:的Mockito和RestTemplate与泛型类型
final URI targetUri = UriComponentsBuilder.fromUriString(baseUri)
.path("/myEntities").build().toUri();
final RequestEntity<Void> request = RequestEntity.get(targetUri).accept(HAL_JSON).build();
final Resources<MyEntity> resourceAccounts = restTemplate.exchange(request, new ResourcesType<MyEntity>() {
}).getBody();
在单元测试中,我嘲讽使用此的Mockito请求 - 响应:
final Resources<MyEntity> myEntities = new Resources<>(myEntityList, links);
final ResponseEntity<Object> response = new ResponseEntity<Object>(myEntities, HttpStatus.OK);
when(restTemplate.exchange(any(RequestEntity.class), any(ResourcesType.class))).thenReturn(response);
它工作正常,但我是因为我没有正确地使用仿制药获得Unchecked invocation exchanged
。
我只是想知道做这件事的正确和防弹的方法是什么?我尝试将ResponseEntity
类型转换为MyEntity
,但这确实会导致编译异常(构造函数ResponseEntity<MyEntity> is undefined
)。