我一直在关注如何创建表,如果它们不存在于当前DataBase中(为了能够在不同的数据库中创建该表,并且可能不具有它们)以及发现,这两项实用主题的在IF语句中间执行GO命令
所以我做了这个查询
IF (NOT EXISTS (SELECT *
FROM INFORMATION_SCHEMA.TABLES
WHERE TABLE_NAME = 'EMAILCONTAS'))
BEGIN
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
SET ANSI_PADDING ON
GO
CREATE TABLE [dbo].[EMAILCONTAS](
[NRSEQEMAILCONTAS] [numeric](8, 0) NOT NULL,
[CDEMAILCONTAS] [varchar](40) NULL,
[MSGEMAILCONTAS] [varchar](4000) NOT NULL,
[CCOEMAIL] [varchar](100) NULL,
[NRSEQOPERADORA] [numeric](8, 0) NOT NULL,
CONSTRAINT [PK_EMAILCONTAS] PRIMARY KEY CLUSTERED
(
[NRSEQEMAILCONTAS] ASC
)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY]
GO
SET ANSI_PADDING OFF
GO
ALTER TABLE [dbo].[EMAILCONTAS] WITH CHECK ADD FOREIGN KEY([NRSEQOPERADORA])
REFERENCES [dbo].[OPERADORA] ([NRSEQOPERADORA])
GO
ALTER TABLE [dbo].[EMAILCONTAS] WITH CHECK ADD CONSTRAINT [FK_EMAILCONTAS_OPERADORA] FOREIGN KEY([NRSEQOPERADORA])
REFERENCES [dbo].[OPERADORA] ([NRSEQOPERADORA])
GO
ALTER TABLE [dbo].[EMAILCONTAS] CHECK CONSTRAINT [FK_EMAILCONTAS_OPERADORA]
GO
END
但是当我执行它时,我在错误列表中找到了它。
Msg 102, Level 15, State 1, Line 5
Incorrect syntax near 'ON'.
但无论如何创建我的表(我把“从PERSON选择*”;上面的代码后,检查错误可能会阻止下一个脚本编译或不和错误阻止它。 。显示此错误:
Msg 156, Level 15, State 1, Line 3
Incorrect syntax near the keyword 'Select'.
有一种方法,以避免它)?当我执行这个查询和表已经存在时,我得到了以下错误。
Msg 102, Level 15, State 1, Line 5
Incorrect syntax near 'ON'.
Msg 2714, Level 16, State 6, Line 2
There is already an object named 'EMAILCONTAS' in the database.
Msg 2714, Level 16, State 5, Line 2
There is already an object named 'FK_EMAILCONTAS_OPERADORA' in the database.
Msg 1750, Level 16, State 0, Line 2
Could not create constraint. See previous errors.
我怎么能做到这一点没有得到这些错误?有没有一种方法可以像这样创建多个代码而没有问题?我究竟做错了什么?
非常感谢,这是有效的。我正在把你的答案作为正确的答案,因为“GO”的解释 – 2012-07-30 13:33:53