jQuery(function ($) {
/* fetch elements and stop form event */
$("form.follow-form").submit(function (e) {
/* stop event */
e.preventDefault();
/* "on request" */
$(this).find('i').addClass('active');
/* send ajax request */
$.post('recycle.php', {
followID: $(this).find('input').val()
}, function() {
/* find and hide button, create element */
$(e.currentTarget)
.find('button').hide()
.after('<span class="following"><span></span>Following!</span>');
});
});
});
的HTML:我的jquery ajax请求没有访问数据库?
<form class="follow-form" method="post" action="recycle.php">
<input name="id" value="$id" type="hidden">
<input name="$tweet" value="$tweet" type="hidden">
<button type="submit" value="Actions" class="btn follow" title="123456">
<i></i><span>recyle</span>
</button>
</form>
reycle.php:
<?php session_start();
include_once ('includes/connect.php');
$id = $_POST['id'];
$tweet =$_POST['tweet'];
$registerlistener = mysql_query("INSERT INTO notes (user_id, user_note,recyle_id,dt) VALUES('".$_SESSION['user_id']."','".$tweet."','".$id."',NOW()");
?>
的问题是,它不是访问recycle.php文件,插入HTML表单的信息到数据库!但它正在做整个jQuery动画!我没有看到最新的问题!
什么是“整个jQuery动画”? – elektronikLexikon 2010-09-17 17:02:40
基本上当我点击reycle按钮时,它变成了文字说“回收” – getaway 2010-09-17 17:04:05
该值'=“$ id”'不是'value =“<?php echo $ id?>”',并且与$ tweet相同' – RobertPitt 2010-09-17 17:36:16