MSBuild正则表达式汇编版本

Question

尝试创建一个MSBuild任务，将我的代码输出到文件夹。除正则表达式外，所有工作都正常。我的代码：当我尝试%(SolnFiles.OutVersion)它出现空白

The item "D:\Dache\INDIVIDUAL.txt" in item list "SolnFiles" does not define a value for metadata "OutVersion". In order to use this metadata, either qualify it by specifying %(SolnFiles.OutVersion), or ensure that all items in this list define a value for this metadata.

：

<Target Name="AfterBuild"> 
    <GetAssemblyIdentity AssemblyFiles="$(OutDir)$(TargetFileName)"> 
    <Output TaskParameter="Assemblies" ItemName="TheVersion" /> 
    </GetAssemblyIdentity> 
    <PropertyGroup> 
    <Pattern>(\d+)\.(\d+)\.(\d+)</Pattern> 
    <In>%(TheVersion.Version)</In> 
    <OutVersion>$([System.Text.RegularExpressions.Regex]::Match($(In), $(Pattern)))</OutVersion> 
    </PropertyGroup> 
    <ItemGroup> 
    <OutputFiles Include="$(OutDir)*" Exclude="*.tmp" /> 
    <SolnFiles Include="$(SolutionDir)INDIVIDUAL.txt;$(SolutionDir)LICENSE.txt;$(SolutionDir)README.md" /> 
    </ItemGroup> 

    <Copy SourceFiles="@(OutputFiles)" DestinationFolder="$(SolutionDir)dache-%(OutVersion)\Tests" SkipUnchangedFiles="true" /> 
    <Copy SourceFiles="@(SolnFiles)" DestinationFolder="$(SolutionDir)dache-%(OutVersion)\" SkipUnchangedFiles="true" /> 
</Target> 

当我运行它，我得到这个错误。我在这里做些愚蠢的事情，它是什么？

Answer 1

带我了解了一些。 PropertyGroup变量引用为$(Var)而ItemGroup输出变量是@()和GetAssemblyIdentity是%() - 所以我改变：

<Copy SourceFiles="@(OutputFiles)" DestinationFolder="$(SolutionDir)dache-%(OutVersion)\Tests" SkipUnchangedFiles="true" /> 
<Copy SourceFiles="@(SolnFiles)" DestinationFolder="$(SolutionDir)dache-%(OutVersion)\" SkipUnchangedFiles="true" /> 

这样：

<Copy SourceFiles="@(OutputFiles)" DestinationFolder="$(SolutionDir)dache-$(OutVersion)\Tests" SkipUnchangedFiles="true" /> 
<Copy SourceFiles="@(SolnFiles)" DestinationFolder="$(SolutionDir)dache-$(OutVersion)\" SkipUnchangedFiles="true" /> 

和它的工作。