狐狸需要时间来解释从头到尾发生的事情。填充以下用户猫鼬
序言:
用户在如下等10人。当用户A登录时,来自10个人中的每个人的X个帖子被拉入视野。
我不知道这是否是正确的做法,并会欣赏更好的做法。但是,我想尝试一下,但它不起作用。
后续型号:
let mongoose = require('mongoose');
let Schema = mongoose.Schema;
let FollowSchema = new Schema({
user: {
type: Schema.Types.ObjectId,
ref: 'User'
},
followers: [{
type: Schema.Types.ObjectId,
ref: 'Card'
}],
following: [{
type: Schema.Types.ObjectId,
ref: 'Card'
}]
});
module.exports = mongoose.model('Follow', FollowSchema);
卡型号
let mongoose = require('mongoose');
let Schema = mongoose.Schema;
let CardSchema = new Schema({
title: String,
content: String,
createdById: {
type: Schema.Types.ObjectId,
ref: 'User'
},
createdBy: {
type: String
}
});
module.exports = mongoose.model('Card', CardSchema);
按照逻辑
当用户A如下用户B,做两件事情:
- 推B的USER_ID到用户现场 '以下'(A是以下B)A至用户B的文档对字段 '跟随'
推USER_ID(B之后是A)
文档router.post('/follow', utils.loginRequired, function(req, res) { const user_id = req.user._id; const follow = req.body.follow_id; let bulk = Follow.collection.initializeUnorderedBulkOp(); bulk.find({ 'user': Types.ObjectId(user_id) }).upsert().updateOne({ $addToSet: { following: Types.ObjectId(follow) } }); bulk.find({ 'user': Types.ObjectId(follow) }).upsert().updateOne({ $addToSet: { followers: Types.ObjectId(user_id) } }) bulk.execute(function(err, doc) { if (err) { return res.json({ 'state': false, 'msg': err }) } res.json({ 'state': true, 'msg': 'Followed' }) })
})
实际DB值
> db.follows.find().pretty()
{
"_id" : ObjectId("59e3e27dace1f14e0a70862d"),
"user" : ObjectId("59e2194177cae833894c9956"),
"following" : [
ObjectId("59e3e618ace1f14e0a708713")
]
}
{
"_id" : ObjectId("59e3e27dace1f14e0a70862e"),
"user" : ObjectId("59e13b2dca5652efc4ca2cf5"),
"followers" : [
ObjectId("59e2194177cae833894c9956"),
ObjectId("59e13b2d27cfed535928c0e7"),
ObjectId("59e3e617149f0a3f1281e849")
]
}
{
"_id" : ObjectId("59e3e71face1f14e0a708770"),
"user" : ObjectId("59e13b2d27cfed535928c0e7"),
"following" : [
ObjectId("59e3e618ace1f14e0a708713"),
ObjectId("59e13b2dca5652efc4ca2cf5"),
ObjectId("59e21942ca5652efc4ca30ab")
]
}
{
"_id" : ObjectId("59e3e71face1f14e0a708771"),
"user" : ObjectId("59e3e618ace1f14e0a708713"),
"followers" : [
ObjectId("59e13b2d27cfed535928c0e7"),
ObjectId("59e2194177cae833894c9956")
]
}
{
"_id" : ObjectId("59e3e72bace1f14e0a708779"),
"user" : ObjectId("59e21942ca5652efc4ca30ab"),
"followers" : [
ObjectId("59e13b2d27cfed535928c0e7"),
ObjectId("59e2194177cae833894c9956"),
ObjectId("59e3e617149f0a3f1281e849")
]
}
{
"_id" : ObjectId("59f0eef155ee5a5897e1a66d"),
"user" : ObjectId("59e3e617149f0a3f1281e849"),
"following" : [
ObjectId("59e21942ca5652efc4ca30ab"),
ObjectId("59e13b2dca5652efc4ca2cf5")
]
}
>
使用上述数据库的结果,这是我的查询:
查询
router.get('/follow/list', utils.loginRequired, function(req, res) {
const user_id = req.user._id;
Follow.findOne({ 'user': Types.ObjectId(user_id) })
.populate('following')
.exec(function(err, doc) {
if (err) {
return res.json({
'state': false,
'msg': err
})
};
console.log(doc.username);
res.json({
'state': true,
'msg': 'Follow list',
'doc': doc
})
})
});
有了上面的查询,从我的猫鼬的一点理解填充,我期望从各拿,卡following
阵列中的用户。
我的理解和期望可能是错误的,但是在这样一个终结之后,这种填充方法好吗?还是我试图解决人口聚集任务?
UPDATE:
感谢您的回答。变得非常接近,但仍然,followingCards
数组不包含结果。这是我目前的Follow
模型的内容:
> db.follows.find().pretty()
{
"_id" : ObjectId("59f24c0555ee5a5897e1b23d"),
"user" : ObjectId("59f24bda1d048d1edad4bda8"),
"following" : [
ObjectId("59f24b3a55ee5a5897e1b1ec"),
ObjectId("59f24bda55ee5a5897e1b22c")
]
}
{
"_id" : ObjectId("59f24c0555ee5a5897e1b23e"),
"user" : ObjectId("59f24b3a55ee5a5897e1b1ec"),
"followers" : [
ObjectId("59f24bda1d048d1edad4bda8")
]
}
{
"_id" : ObjectId("59f24c8855ee5a5897e1b292"),
"user" : ObjectId("59f24bda55ee5a5897e1b22c"),
"followers" : [
ObjectId("59f24bda1d048d1edad4bda8")
]
}
>
以下是目前所有的内容,我从Card
型号有:
> db.cards.find().pretty()
{
"_id" : ObjectId("59f24bc01d048d1edad4bda6"),
"title" : "A day or two with Hubtel's HTTP API",
"content" : "a day or two",
"external" : "",
"slug" : "a-day-or-two-with-hubtels-http-api-df77056d",
"createdBy" : "seanmavley",
"createdById" : ObjectId("59f24b391d048d1edad4bda5"),
"createdAt" : ISODate("2017-10-26T20:55:28.293Z"),
"__v" : 0
}
{
"_id" : ObjectId("59f24c5f1d048d1edad4bda9"),
"title" : "US couple stole goods worth $1.2m from Amazon",
"content" : "for what",
"external" : "https://bbc.com",
"slug" : "us-couple-stole-goods-worth-dollar12m-from-amazon-49b0a524",
"createdBy" : "nkansahrexford",
"createdById" : ObjectId("59f24bda1d048d1edad4bda8"),
"createdAt" : ISODate("2017-10-26T20:58:07.793Z"),
"__v" : 0
}
与你(@Veeram)的填充虚拟实例,这里的响应我得到:
{"state":true,"msg":"Follow list","doc":{"_id":"59f24c0555ee5a5897e1b23d","user":"59f24bda1d048d1edad4bda8","following":["59f24b3a55ee5a5897e1b1ec","59f24bda55ee5a5897e1b22c"],"followers":[],"id":"59f24c0555ee5a5897e1b23d","followingCards":[]}}
followingCards
数组是空的。
使用$lookup
查询,另一方面直接返回[]
我可能失去了一些东西?
编辑您的架构你的问题。 – Mikey
@JohnnyHK好的。会做。 – Rexford
填充仅适用于在保存前将参考文件推送到Follow.following! –