2013-02-13 59 views
0

我是iphone新手,我尝试了很多,但没有找到任何解决方案。IPHONE的内部阵列

我想这样

[ 
     { 
      "longitude" : -71.449162, 
      "latitude" : 42.734752 
     }, 
     { 
      "longitude" : -71.447343, 
      "latitude" : 42.735636 
     }, 
     { 
      "longitude" : -71.446246, 
      "latitude" : 42.735807 
     } 
    ] 

输出,但我得到的输出喜欢这个

"longitude":"(
    "42.713974", 
    "-71.449432", 
    "42.713757", 
    "-71.449471", 
    "42.713474", 
    "-71.449516", 

)", "latitude":"(
    "42.713974", 
    "-71.449432", 
    "42.713757", 
    "-71.449471", 
    "42.713474", 
    "-71.449516", 

) 

我想在不同的阵列经度和纬度值。

感谢

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请发布生成,存储和打印这些数据的代码。 – 2013-02-13 07:37:37

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@Nirav Ranpara我的回答很有用吗? – IKKA 2013-02-13 11:15:20

回答

2

请试试这个:

NSMutableArray *mytest = [[NSMutableArray alloc]initWithObjects:@"-71.449162",@"-71.447343",@"-71.446246",nil]; 

NSMutableArray *mytest1 = [[NSMutableArray alloc]initWithObjects:@"42.734752",@"42.735636",@"42.735807",nil]; 

NSMutableArray *testArray = [[NSMutableArray alloc]init]; 
for (int i = 0; i< 3; i++) { 
NSMutableDictionary *dict = [[NSMutableDictionary alloc] init]; 
[dict setObject:[mytest objectAtIndex:i] forKey:@"longitude"]; 
[dict setObject:[mytest1 objectAtIndex:i] forKey:@"latitude"]; 
[testArray addObject:dict]; 


} 

NSLog(@"my array is : %@",testArray); 

NSError *error; 

NSData *jsonData = [NSJSONSerialization dataWithJSONObject:testArray options:NSJSONWritingPrettyPrinted error:&error]; 

NSString *jsonString = [[NSString alloc]initWithData:jsonData encoding:NSUTF8StringEncoding]; 

NSLog(@"json string is : \n%@",jsonString); 
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但我想 “[” 这不是 “(” – 2013-02-13 11:32:44

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@NiravRanpara试试这个代码... NSError *错误; 的NSData * jsonData = [NSJSONSerialization dataWithJSONObject:testArray选项:NSJSONWritingPrettyPrinted错误:&error]; NSString * jsonString = [[NSString alloc] initWithData:jsonData encoding:NSUTF8StringEncoding]; NSLog(@“json string is:\ n%@”,jsonString); – IKKA 2013-02-13 14:52:20

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@NiravRanpara,上面的评论是有帮助的或者没有? – IKKA 2013-02-14 05:54:15

0

商店的纬度和经度作为单独的阵列字符串格式,并尝试使用此代码

NSMutableArray * totalArray=[[NSMutableArray alloc]init]; 
for(int i=0;i<3;i++) 
{ 
NSArray* temp=[[NSArray alloc]initwithObjects:[NSString stringWithFormat:@"Latitude%@",[latitudearray objectAtIndex:i]],[NSString stringWithFormat:@"Longitudee%@",[longitudearray objectAtIndex:i]],nil]; 
[totalArray addObject:temp]; 
} 

    NSLog(@"%@",totalArray); 

希望这有助于...

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但我想 “[” 这不是 “(” – 2013-02-13 12:23:45